Files
2021-Postgraduate-408/DailySummary/计算两个日期间的天数.cpp
2019-03-27 10:36:16 +08:00

39 lines
812 B
C++

#include <cstdio>
int month[13][2] = {
{0, 0}, {31, 31}, {28, 29}, {31, 31}, {30, 30}, {31, 31}, {30, 30}, {31, 31},
{31, 31}, {30, 30}, {31, 31}, {30, 30}, {31, 31}
};
bool isLeap(int year){
return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
}
int main(){
int time1, y1, m1, d1;
int time2, y2, m2, d2;
while(scanf("%d%d", &time1, &time2) != EOF){
if(time1 > time2){
int temp = time1;
time1 = time2;
time2 = temp;
}
y1 = time1 / 10000, m1 = time1 % 10000 / 100, d1 = time1 % 100;
y2 = time2 / 10000, m2 = time2 % 10000 / 100, d2 = time2 % 100;
int ans = 1;
while(y1 < y2 || m1 < m2 || d1 < d2){
d1++;
if(d1 == month[m1][isLeap(y1)] + 1){
m1++;
d1 = 1;
}
if(m1 == 13){
y1++;
m1 = 1;
}
ans++;
}
printf("%d\n", ans);
}
return 0;
}