//
// Created by kim on 2020/6/17.
//

#include <stdio.h>

//下面四种函数的时间复杂度值得分析一二

//逐步递增型爱你
void LoveYou0(int n){
    int i=1;
    while (i<=n){
        printf("I love you %d \n",i);
        i++;
    }
    printf("I love you more than %d\n",n);
}

//嵌套循环型爱你
void loveYou1(int n){
    int i=1;
    while (i<=n){
        i++;
        printf("I love you %d\n",i);
        for (int j = 1; j <n ; j++) {
            printf("I love you too\n");
        }
    }
    printf("I love you more than %d\n",n);
}
//指数递增型爱你
void loveYou2(int n){
    int i=1;
    while (i<=n){
        printf("I love you %d\n",i);
        i=i*2;
    }
    printf("I love you more than %d\n ",n);
}

//搜索数字型爱你
void loveYou3(int flag[],int n){
    printf("I Am kim\n");
    for (int i = 0; i < n; i++) {
        //我觉这里应该是数组长度
        if (flag[i]==n){
            printf("I love you %d\n",n);
            break;//找到之后就跳出循环
        }
    }
}
//递归型爱你
void loveYou4(int n){
    int a,b,c;
    if (n>1){
        loveYou4(n-1);
    }
    printf("I love you %d\n",n);
}//递归调用会带来多余的内存开销

//测试函数
void Test(){
    LoveYou0(30);
    loveYou1(30);
    loveYou2(30);

    int array[5]={2,10,100,1000,10000};
    //声明一个数组并初始化
    loveYou3(array,10);
    loveYou4(4);

}

int main(){
    Test();
    return 0;
}