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\subsection{抽象型}
\section{二次型最值}
若$A$的特征值大小排序$\lambda_1\leqslant\lambda_2\leqslant\cdots\leqslant\lambda_n$,则:
\begin{itemize}
\item $\lambda_1x^Tx\leqslant x^TAx\leqslant\lambda_nx^Tx$。
\item 若$x^Tx=1$,则$f_{\min}=\lambda_1$,$f_{\max}=\lambda_n$。
\end{itemize}
\end{document}