{ "cells": [ { "cell_type": "markdown", "id": "73bd968b-d970-4a05-94ef-4e7abf990827", "metadata": {}, "source": [ "Chapter 04\n", "\n", "# 矩阵标量乘法\n", "Book_4《矩阵力量》 | 鸢尾花书:从加减乘除到机器学习 (第二版)" ] }, { "cell_type": "markdown", "id": "0cf4bb7f-f36d-486a-9187-a6f4f7ec18ba", "metadata": {}, "source": [ "该代码定义了一个标量 $k = 2$ 和一个 $2 \\times 2$ 矩阵 $X$:\n", "\n", "$$\n", "X = \\begin{bmatrix} 1 & 2 \\\\ 3 & 4 \\end{bmatrix}\n", "$$\n", "\n", "代码随后计算了标量 $k$ 与矩阵 $X$ 的乘积,得到的结果矩阵 $k \\times X$ 为:\n", "\n", "$$\n", "k \\times X = 2 \\times \\begin{bmatrix} 1 & 2 \\\\ 3 & 4 \\end{bmatrix} = \\begin{bmatrix} 2 & 4 \\\\ 6 & 8 \\end{bmatrix}\n", "$$\n", "\n", "代码展示了使用 `np.dot` 函数和直接标量乘法来实现标量与矩阵乘积的两种方法。" ] }, { "cell_type": "markdown", "id": "9b646351-bc61-4c43-96ed-a265eb25eaac", "metadata": {}, "source": [ "## 导入所需库" ] }, { "cell_type": "code", "execution_count": 1, "id": "9a74e2ab-fc70-43a4-85f6-3ddeeacfc5ab", "metadata": {}, "outputs": [], "source": [ "import numpy as np # 导入NumPy库,用于数值计算" ] }, { "cell_type": "markdown", "id": "6bf76475-2000-4adb-82bf-33664ee781da", "metadata": {}, "source": [ "## 定义标量和矩阵" ] }, { "cell_type": "code", "execution_count": 2, "id": "e74e9afd-6c86-4ccd-bd9e-4382bfe0c31f", "metadata": {}, "outputs": [], "source": [ "k = 2 # 定义标量k" ] }, { "cell_type": "code", "execution_count": 3, "id": "db0ca529-60e7-4093-8942-8976a5bc8b29", "metadata": {}, "outputs": [], "source": [ "X = [[1, 2], \n", " [3, 4]] # 定义矩阵X" ] }, { "cell_type": "markdown", "id": "8a306144-ae4b-4b29-9b1a-9a4282ef2f21", "metadata": {}, "source": [ "## 标量与矩阵的乘法" ] }, { "cell_type": "code", "execution_count": 4, "id": "33380485-bdda-4392-8ace-7e11690f111b", "metadata": {}, "outputs": [ { "data": { "text/plain": [ "array([[2, 4],\n", " [6, 8]])" ] }, "execution_count": 4, "metadata": {}, "output_type": "execute_result" } ], "source": [ "k_times_X = np.dot(k, X) # 使用np.dot计算k和X的标量乘法\n", "k_times_X" ] }, { "cell_type": "code", "execution_count": 5, "id": "be39b596-ea34-4108-9447-e3a46d21f91c", "metadata": {}, "outputs": [ { "data": { "text/plain": [ "matrix([[2, 4],\n", " [6, 8]])" ] }, "execution_count": 5, "metadata": {}, "output_type": "execute_result" } ], "source": [ "k_times_X_2 = k * np.matrix(X) # 使用*操作符计算k和X的标量乘法\n", "k_times_X_2" ] }, { "cell_type": "code", "execution_count": null, "id": "85a80909-2aac-49ed-bb7a-f8cc6b80ee7d", "metadata": {}, "outputs": [], "source": [] }, { "cell_type": "code", "execution_count": null, "id": "ecd322f4-f919-4be2-adc3-69d28ef25e69", "metadata": {}, "outputs": [], "source": [] } ], "metadata": { "kernelspec": { "display_name": "Python 3 (ipykernel)", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.12.7" } }, "nbformat": 4, "nbformat_minor": 5 }