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Retranslate the complete English edition from Simplified Chinese (#2010)

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* Retranslate the complete English edition from Simplified Chinese

* Polish three English explanations after reader-focused review
This commit is contained in:
Yudong Jin
2026-10-31 03:35:51 +08:00
committed by GitHub
parent ef46e2ed95
commit 14c314c08c
1502 changed files with 29459 additions and 23517 deletions
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26
en/codes/cpp/chapter_dynamic_programming/coin_change.cpp
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@@ -6,24 +6,24 @@
#include "../utils/common.hpp"
/* Coin change: Dynamic programming */
/* Coin change: dynamic programming */
int coinChangeDP(vector<int> &coins, int amt) {
int n = coins.size();
int MAX = amt + 1;
// Initialize dp table
// Initialize the dp table
vector<vector<int>> dp(n + 1, vector<int>(amt + 1, 0));
// State transition: first row and first column
// State transitions: first row and first column
for (int a = 1; a <= amt; a++) {
dp[0][a] = MAX;
}
// State transition: rest of the rows and columns
// State transitions: remaining rows and columns
for (int i = 1; i <= n; i++) {
for (int a = 1; a <= amt; a++) {
if (coins[i - 1] > a) {
// If exceeds target amount, don't select coin i
// If the coin exceeds the target amount, do not choose coin i
dp[i][a] = dp[i - 1][a];
} else {
// The smaller value between not selecting and selecting coin i
// Take the smaller result of not choosing and choosing coin i
dp[i][a] = min(dp[i - 1][a], dp[i][a - coins[i - 1]] + 1);
}
}
@@ -31,21 +31,21 @@ int coinChangeDP(vector<int> &coins, int amt) {
return dp[n][amt] != MAX ? dp[n][amt] : -1;
}
/* Coin change: Space-optimized dynamic programming */
/* Coin change: space-optimized dynamic programming */
int coinChangeDPComp(vector<int> &coins, int amt) {
int n = coins.size();
int MAX = amt + 1;
// Initialize dp table
// Initialize the dp table
vector<int> dp(amt + 1, MAX);
dp[0] = 0;
// State transition
// State transitions
for (int i = 1; i <= n; i++) {
for (int a = 1; a <= amt; a++) {
if (coins[i - 1] > a) {
// If exceeds target amount, don't select coin i
// If the coin exceeds the target amount, do not choose coin i
dp[a] = dp[a];
} else {
// The smaller value between not selecting and selecting coin i
// Take the smaller result of not choosing and choosing coin i
dp[a] = min(dp[a], dp[a - coins[i - 1]] + 1);
}
}
@@ -60,11 +60,11 @@ int main() {
// Dynamic programming
int res = coinChangeDP(coins, amt);
cout << "Minimum number of coins needed to make target amount is " << res << endl;
cout << "Minimum number of coins needed to reach the target amount: " << res << endl;
// Space-optimized dynamic programming
res = coinChangeDPComp(coins, amt);
cout << "Minimum number of coins needed to make target amount is " << res << endl;
cout << "Minimum number of coins needed to reach the target amount: " << res << endl;
return 0;
}