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https://github.com/krahets/hello-algo.git
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Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
This commit is contained in:
@@ -8,13 +8,13 @@
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/* Bubble sort */
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void bubbleSort(vector<int> &nums) {
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// Outer loop: unsorted range is [0, i]
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// Outer loop: the unsorted range is [0, i]
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for (int i = nums.size() - 1; i > 0; i--) {
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// Inner loop: swap the largest element in the unsorted range [0, i] to the rightmost end of that range
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// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
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for (int j = 0; j < i; j++) {
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if (nums[j] > nums[j + 1]) {
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// Swap nums[j] and nums[j + 1]
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// Using std::swap() function here
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// Use the std::swap() function here
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swap(nums[j], nums[j + 1]);
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}
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}
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@@ -23,33 +23,33 @@ void bubbleSort(vector<int> &nums) {
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/* Bubble sort (flag optimization)*/
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void bubbleSortWithFlag(vector<int> &nums) {
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// Outer loop: unsorted range is [0, i]
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// Outer loop: the unsorted range is [0, i]
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for (int i = nums.size() - 1; i > 0; i--) {
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bool flag = false; // Initialize flag
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// Inner loop: swap the largest element in the unsorted range [0, i] to the rightmost end of that range
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bool flag = false; // Initialize the flag
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// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
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for (int j = 0; j < i; j++) {
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if (nums[j] > nums[j + 1]) {
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// Swap nums[j] and nums[j + 1]
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// Using std::swap() function here
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// Use the std::swap() function here
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swap(nums[j], nums[j + 1]);
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flag = true; // Record element swap
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flag = true; // Record that a swap occurred
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}
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}
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if (!flag)
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break; // No elements were swapped in this round of "bubbling", exit directly
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break; // Exit immediately if this pass made no swaps
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}
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}
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/* Driver Code */
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/* Driver code */
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int main() {
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vector<int> nums = {4, 1, 3, 1, 5, 2};
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bubbleSort(nums);
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cout << "After bubble sort completes, nums = ";
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cout << "After bubble sort, nums = ";
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printVector(nums);
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vector<int> nums1 = {4, 1, 3, 1, 5, 2};
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bubbleSortWithFlag(nums1);
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cout << "After bubble sort completes, nums1 = ";
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cout << "After bubble sort, nums1 = ";
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printVector(nums1);
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return 0;
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@@ -8,22 +8,22 @@
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/* Bucket sort */
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void bucketSort(vector<float> &nums) {
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// Initialize k = n/2 buckets, expected to allocate 2 elements per bucket
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// Initialize k = n/2 buckets, expecting 2 elements per bucket
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int k = nums.size() / 2;
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vector<vector<float>> buckets(k);
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// 1. Distribute array elements into various buckets
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// 1. Distribute the array elements among the buckets
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for (float num : nums) {
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// Input data range is [0, 1), use num * k to map to index range [0, k-1]
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// The input range is [0, 1); use num * k to map each value to an index in [0, k-1]
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int i = num * k;
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// Add num to bucket bucket_idx
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// Add num to bucket i
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buckets[i].push_back(num);
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}
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// 2. Sort each bucket
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for (vector<float> &bucket : buckets) {
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// Use built-in sorting function, can also replace with other sorting algorithms
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// Use the built-in sorting function, or replace it with another sorting algorithm
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sort(bucket.begin(), bucket.end());
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}
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// 3. Traverse buckets to merge results
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// 3. Traverse the buckets to combine the results
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int i = 0;
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for (vector<float> &bucket : buckets) {
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for (float num : bucket) {
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@@ -32,12 +32,12 @@ void bucketSort(vector<float> &nums) {
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}
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}
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/* Driver Code */
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/* Driver code */
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int main() {
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// Assume input data is floating point, interval [0, 1)
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// Assume the input consists of floating-point numbers in [0, 1)
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vector<float> nums = {0.49f, 0.96f, 0.82f, 0.09f, 0.57f, 0.43f, 0.91f, 0.75f, 0.15f, 0.37f};
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bucketSort(nums);
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cout << "After bucket sort completes, nums = ";
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cout << "After bucket sort, nums = ";
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printVector(nums);
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return 0;
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@@ -7,20 +7,20 @@
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#include "../utils/common.hpp"
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/* Counting sort */
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// Simple implementation, cannot be used for sorting objects
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// Simple implementation; cannot be used to sort objects
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void countingSortNaive(vector<int> &nums) {
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// 1. Count the maximum element m in the array
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// 1. Find the maximum array element m
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int m = 0;
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for (int num : nums) {
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m = max(m, num);
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}
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// 2. Count the occurrence of each number
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// counter[num] represents the occurrence of num
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// 2. Count the occurrences of each number
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// counter[num] is the number of occurrences of num
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vector<int> counter(m + 1, 0);
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for (int num : nums) {
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counter[num]++;
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}
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// 3. Traverse counter, filling each element back into the original array nums
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// 3. Traverse counter and fill the original array nums with the elements
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int i = 0;
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for (int num = 0; num < m + 1; num++) {
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for (int j = 0; j < counter[num]; j++, i++) {
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@@ -30,47 +30,47 @@ void countingSortNaive(vector<int> &nums) {
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}
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/* Counting sort */
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// Complete implementation, can sort objects and is a stable sort
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// Stable implementation that can be adapted to sort objects
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void countingSort(vector<int> &nums) {
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// 1. Count the maximum element m in the array
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// 1. Find the maximum array element m
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int m = 0;
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for (int num : nums) {
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m = max(m, num);
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}
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// 2. Count the occurrence of each number
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// counter[num] represents the occurrence of num
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// 2. Count the occurrences of each number
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// counter[num] is the number of occurrences of num
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vector<int> counter(m + 1, 0);
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for (int num : nums) {
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counter[num]++;
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}
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// 3. Calculate the prefix sum of counter, converting "occurrence count" to "tail index"
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// counter[num]-1 is the last index where num appears in res
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// 3. Compute prefix sums of counter to convert occurrence counts into end positions
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// That is, counter[num]-1 is the index of the last occurrence of num in res
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for (int i = 0; i < m; i++) {
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counter[i + 1] += counter[i];
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}
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// 4. Traverse nums in reverse order, placing each element into the result array res
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// Initialize the array res to record results
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// 4. Traverse nums in reverse and place each element in the result array res
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// Initialize array res to store the result
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int n = nums.size();
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vector<int> res(n);
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for (int i = n - 1; i >= 0; i--) {
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int num = nums[i];
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res[counter[num] - 1] = num; // Place num at the corresponding index
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counter[num]--; // Decrement the prefix sum by 1, getting the next index to place num
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counter[num]--; // Decrement the prefix sum by 1 to determine where to place the next occurrence of num
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}
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// Use result array res to overwrite the original array nums
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// Overwrite the original array nums with the result array res
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nums = res;
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}
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/* Driver Code */
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/* Driver code */
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int main() {
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vector<int> nums = {1, 0, 1, 2, 0, 4, 0, 2, 2, 4};
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countingSortNaive(nums);
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cout << "After counting sort (cannot sort objects) completes, nums = ";
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cout << "After counting sort (without support for objects), nums = ";
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printVector(nums);
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vector<int> nums1 = {1, 0, 1, 2, 0, 4, 0, 2, 2, 4};
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countingSort(nums1);
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cout << "After counting sort completes, nums1 = ";
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cout << "After counting sort, nums1 = ";
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printVector(nums1);
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return 0;
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@@ -6,10 +6,10 @@
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#include "../utils/common.hpp"
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/* Heap length is n, start heapifying node i, from top to bottom */
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/* Sift down from node i in a heap of size n */
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void siftDown(vector<int> &nums, int n, int i) {
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while (true) {
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// If node i is largest or indices l, r are out of bounds, no need to continue heapify, break
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// Find the node with the largest value among i, l, and r, and store its index in ma
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int l = 2 * i + 1;
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int r = 2 * i + 2;
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int ma = i;
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@@ -17,37 +17,37 @@ void siftDown(vector<int> &nums, int n, int i) {
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ma = l;
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if (r < n && nums[r] > nums[ma])
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ma = r;
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// Swap two nodes
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// Stop if node i is largest or both child indices l and r are out of bounds
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if (ma == i) {
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break;
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}
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// Swap two nodes
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// Swap the two nodes
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swap(nums[i], nums[ma]);
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// Loop downwards heapification
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// Continue sifting down
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i = ma;
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}
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}
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/* Heap sort */
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void heapSort(vector<int> &nums) {
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// Build heap operation: heapify all nodes except leaves
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// Build the heap by sifting down from every non-leaf node
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for (int i = nums.size() / 2 - 1; i >= 0; --i) {
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siftDown(nums, nums.size(), i);
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}
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// Extract the largest element from the heap and repeat for n-1 rounds
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// Extract the largest element from the heap, repeating for n-1 rounds
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for (int i = nums.size() - 1; i > 0; --i) {
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// Delete node
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// Swap the root with the rightmost leaf on the last level (the first and last elements of the current heap)
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swap(nums[0], nums[i]);
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// Start heapifying the root node, from top to bottom
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// Sift down starting at the root
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siftDown(nums, i, 0);
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}
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}
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/* Driver Code */
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/* Driver code */
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int main() {
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vector<int> nums = {4, 1, 3, 1, 5, 2};
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heapSort(nums);
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cout << "After heap sort completes, nums = ";
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cout << "After heap sort, nums = ";
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printVector(nums);
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return 0;
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@@ -8,23 +8,23 @@
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/* Insertion sort */
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void insertionSort(vector<int> &nums) {
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// Outer loop: sorted interval is [0, i-1]
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// Outer loop: the sorted range is [0, i-1]
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for (int i = 1; i < nums.size(); i++) {
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int base = nums[i], j = i - 1;
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// Inner loop: insert base into the correct position within the sorted interval [0, i-1]
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// Inner loop: insert base at the correct position in the sorted range [0, i-1]
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while (j >= 0 && nums[j] > base) {
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nums[j + 1] = nums[j]; // Move nums[j] to the right by one position
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nums[j + 1] = nums[j]; // Shift nums[j] one position to the right
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j--;
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}
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nums[j + 1] = base; // Assign base to the correct position
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nums[j + 1] = base; // Place base at the correct position
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}
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}
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/* Driver Code */
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/* Driver code */
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int main() {
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vector<int> nums = {4, 1, 3, 1, 5, 2};
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insertionSort(nums);
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cout << "After insertion sort completes, nums = ";
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cout << "After insertion sort, nums = ";
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printVector(nums);
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return 0;
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@@ -6,14 +6,14 @@
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#include "../utils/common.hpp"
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/* Merge left subarray and right subarray */
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/* Merge the left and right subarrays */
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void merge(vector<int> &nums, int left, int mid, int right) {
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// Left subarray interval is [left, mid], right subarray interval is [mid+1, right]
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// Create a temporary array tmp to store the merged results
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// The left subarray spans [left, mid], and the right subarray spans [mid+1, right]
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// Create a temporary array tmp to store the merged result
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vector<int> tmp(right - left + 1);
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// Initialize the start indices of the left and right subarrays
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// Initialize the starting indices of the left and right subarrays
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int i = left, j = mid + 1, k = 0;
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// While both subarrays still have elements, compare and copy the smaller element into the temporary array
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// While both subarrays have elements remaining, compare them and copy the smaller element into the temporary array
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while (i <= mid && j <= right) {
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if (nums[i] <= nums[j])
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tmp[k++] = nums[i++];
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@@ -27,7 +27,7 @@ void merge(vector<int> &nums, int left, int mid, int right) {
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while (j <= right) {
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tmp[k++] = nums[j++];
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}
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// Copy the elements from the temporary array tmp back to the original array nums at the corresponding interval
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// Copy the elements of temporary array tmp back into the corresponding range of the original array nums
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for (k = 0; k < tmp.size(); k++) {
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nums[left + k] = tmp[k];
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}
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@@ -35,23 +35,23 @@ void merge(vector<int> &nums, int left, int mid, int right) {
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/* Merge sort */
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void mergeSort(vector<int> &nums, int left, int right) {
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// Termination condition
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// Base case
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if (left >= right)
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return; // Terminate recursion when subarray length is 1
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// Divide and conquer stage
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int mid = left + (right - left) / 2; // Calculate midpoint
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mergeSort(nums, left, mid); // Recursively process the left subarray
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mergeSort(nums, mid + 1, right); // Recursively process the right subarray
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// Merge stage
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return; // Stop recursing when the subarray has at most one element
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// Divide phase
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int mid = left + (right - left) / 2; // Calculate the midpoint
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mergeSort(nums, left, mid); // Recurse on the left subarray
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mergeSort(nums, mid + 1, right); // Recurse on the right subarray
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// Merge phase
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merge(nums, left, mid, right);
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}
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/* Driver Code */
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/* Driver code */
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int main() {
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/* Merge sort */
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vector<int> nums = {7, 3, 2, 6, 0, 1, 5, 4};
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mergeSort(nums, 0, nums.size() - 1);
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cout << "After merge sort completes, nums = ";
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cout << "After merge sort, nums = ";
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printVector(nums);
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return 0;
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@@ -9,30 +9,30 @@
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/* Quick sort class */
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class QuickSort {
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private:
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/* Sentinel partition */
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/* Two-pointer partitioning */
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static int partition(vector<int> &nums, int left, int right) {
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// Use nums[left] as the pivot
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int i = left, j = right;
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while (i < j) {
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while (i < j && nums[j] >= nums[left])
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j--; // Search from right to left for the first element smaller than the pivot
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j--; // Scan from right to left for the first element smaller than the pivot
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while (i < j && nums[i] <= nums[left])
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i++; // Search from left to right for the first element greater than the pivot
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i++; // Scan from left to right for the first element larger than the pivot
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swap(nums[i], nums[j]); // Swap these two elements
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}
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swap(nums[i], nums[left]); // Swap the pivot to the boundary between the two subarrays
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return i; // Return the index of the pivot
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swap(nums[i], nums[left]); // Swap the pivot into the boundary position between the two subarrays
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return i; // Return the pivot index
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}
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public:
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/* Quick sort */
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static void quickSort(vector<int> &nums, int left, int right) {
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// Terminate recursion when subarray length is 1
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// Stop recursing when the subarray has at most one element
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if (left >= right)
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return;
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// Sentinel partition
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// Two-pointer partitioning
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int pivot = partition(nums, left, right);
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// Recursively process the left subarray and right subarray
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// Recurse on the left and right subarrays
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quickSort(nums, left, pivot - 1);
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quickSort(nums, pivot + 1, right);
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}
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@@ -45,40 +45,40 @@ class QuickSortMedian {
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static int medianThree(vector<int> &nums, int left, int mid, int right) {
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int l = nums[left], m = nums[mid], r = nums[right];
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if ((l <= m && m <= r) || (r <= m && m <= l))
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return mid; // m is between l and r
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return mid; // m lies between l and r
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if ((m <= l && l <= r) || (r <= l && l <= m))
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return left; // l is between m and r
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return left; // l lies between m and r
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return right;
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}
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/* Sentinel partition (median of three) */
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/* Two-pointer partitioning (median of three) */
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static int partition(vector<int> &nums, int left, int right) {
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// Select the median of three candidate elements
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int med = medianThree(nums, left, (left + right) / 2, right);
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// Swap the median to the array's leftmost position
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// Swap the median into the leftmost position of the current subarray
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swap(nums[left], nums[med]);
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// Use nums[left] as the pivot
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int i = left, j = right;
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while (i < j) {
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while (i < j && nums[j] >= nums[left])
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j--; // Search from right to left for the first element smaller than the pivot
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j--; // Scan from right to left for the first element smaller than the pivot
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while (i < j && nums[i] <= nums[left])
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i++; // Search from left to right for the first element greater than the pivot
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i++; // Scan from left to right for the first element larger than the pivot
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swap(nums[i], nums[j]); // Swap these two elements
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}
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swap(nums[i], nums[left]); // Swap the pivot to the boundary between the two subarrays
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return i; // Return the index of the pivot
|
||||
swap(nums[i], nums[left]); // Swap the pivot into the boundary position between the two subarrays
|
||||
return i; // Return the pivot index
|
||||
}
|
||||
|
||||
public:
|
||||
/* Quick sort */
|
||||
static void quickSort(vector<int> &nums, int left, int right) {
|
||||
// Terminate recursion when subarray length is 1
|
||||
// Stop recursing when the subarray has at most one element
|
||||
if (left >= right)
|
||||
return;
|
||||
// Sentinel partition
|
||||
// Two-pointer partitioning
|
||||
int pivot = partition(nums, left, right);
|
||||
// Recursively process the left subarray and right subarray
|
||||
// Recurse on the left and right subarrays
|
||||
quickSort(nums, left, pivot - 1);
|
||||
quickSort(nums, pivot + 1, right);
|
||||
}
|
||||
@@ -87,58 +87,58 @@ class QuickSortMedian {
|
||||
/* Quick sort class (recursion depth optimization) */
|
||||
class QuickSortTailCall {
|
||||
private:
|
||||
/* Sentinel partition */
|
||||
/* Two-pointer partitioning */
|
||||
static int partition(vector<int> &nums, int left, int right) {
|
||||
// Use nums[left] as the pivot
|
||||
int i = left, j = right;
|
||||
while (i < j) {
|
||||
while (i < j && nums[j] >= nums[left])
|
||||
j--; // Search from right to left for the first element smaller than the pivot
|
||||
j--; // Scan from right to left for the first element smaller than the pivot
|
||||
while (i < j && nums[i] <= nums[left])
|
||||
i++; // Search from left to right for the first element greater than the pivot
|
||||
i++; // Scan from left to right for the first element larger than the pivot
|
||||
swap(nums[i], nums[j]); // Swap these two elements
|
||||
}
|
||||
swap(nums[i], nums[left]); // Swap the pivot to the boundary between the two subarrays
|
||||
return i; // Return the index of the pivot
|
||||
swap(nums[i], nums[left]); // Swap the pivot into the boundary position between the two subarrays
|
||||
return i; // Return the pivot index
|
||||
}
|
||||
|
||||
public:
|
||||
/* Quick sort (recursion depth optimization) */
|
||||
static void quickSort(vector<int> &nums, int left, int right) {
|
||||
// Terminate when subarray length is 1
|
||||
// Stop when the subarray has at most one element
|
||||
while (left < right) {
|
||||
// Sentinel partition operation
|
||||
// Perform two-pointer partitioning
|
||||
int pivot = partition(nums, left, right);
|
||||
// Perform quick sort on the shorter of the two subarrays
|
||||
// Apply quick sort to the shorter of the two subarrays
|
||||
if (pivot - left < right - pivot) {
|
||||
quickSort(nums, left, pivot - 1); // Recursively sort the left subarray
|
||||
left = pivot + 1; // Remaining unsorted interval is [pivot + 1, right]
|
||||
left = pivot + 1; // The remaining unsorted range is [pivot + 1, right]
|
||||
} else {
|
||||
quickSort(nums, pivot + 1, right); // Recursively sort the right subarray
|
||||
right = pivot - 1; // Remaining unsorted interval is [left, pivot - 1]
|
||||
right = pivot - 1; // The remaining unsorted range is [left, pivot - 1]
|
||||
}
|
||||
}
|
||||
}
|
||||
};
|
||||
|
||||
/* Driver Code */
|
||||
/* Driver code */
|
||||
int main() {
|
||||
/* Quick sort */
|
||||
vector<int> nums{2, 4, 1, 0, 3, 5};
|
||||
QuickSort::quickSort(nums, 0, nums.size() - 1);
|
||||
cout << "After quick sort completes, nums = ";
|
||||
cout << "After quick sort, nums = ";
|
||||
printVector(nums);
|
||||
|
||||
/* Quick sort (recursion depth optimization) */
|
||||
/* Quick sort (median pivot optimization) */
|
||||
vector<int> nums1 = {2, 4, 1, 0, 3, 5};
|
||||
QuickSortMedian::quickSort(nums1, 0, nums1.size() - 1);
|
||||
cout << "After quick sort (median pivot optimization), nums = ";
|
||||
cout << "After quick sort with median-of-three pivot selection, nums1 = ";
|
||||
printVector(nums1);
|
||||
|
||||
/* Quick sort (recursion depth optimization) */
|
||||
vector<int> nums2 = {2, 4, 1, 0, 3, 5};
|
||||
QuickSortTailCall::quickSort(nums2, 0, nums2.size() - 1);
|
||||
cout << "After quick sort (recursion depth optimization), nums = ";
|
||||
cout << "After quick sort with recursion-depth optimization, nums2 = ";
|
||||
printVector(nums2);
|
||||
|
||||
return 0;
|
||||
|
||||
@@ -6,59 +6,59 @@
|
||||
|
||||
#include "../utils/common.hpp"
|
||||
|
||||
/* Get the k-th digit of element num, where exp = 10^(k-1) */
|
||||
/* Get the k-th digit of num, where exp = 10^(k-1) */
|
||||
int digit(int num, int exp) {
|
||||
// Passing exp instead of k can avoid repeated expensive exponentiation here
|
||||
// Passing exp instead of k avoids repeatedly performing expensive exponentiation here
|
||||
return (num / exp) % 10;
|
||||
}
|
||||
|
||||
/* Counting sort (based on nums k-th digit) */
|
||||
/* Counting sort (sort nums by the k-th digit) */
|
||||
void countingSortDigit(vector<int> &nums, int exp) {
|
||||
// Decimal digit range is 0~9, therefore need a bucket array of length 10
|
||||
// Decimal digits range from 0 to 9, so the bucket array needs length 10
|
||||
vector<int> counter(10, 0);
|
||||
int n = nums.size();
|
||||
// Count the occurrence of digits 0~9
|
||||
// Count the occurrences of each digit from 0 to 9
|
||||
for (int i = 0; i < n; i++) {
|
||||
int d = digit(nums[i], exp); // Get the k-th digit of nums[i], noted as d
|
||||
counter[d]++; // Count the occurrence of digit d
|
||||
int d = digit(nums[i], exp); // Get the k-th digit of nums[i] and store it in d
|
||||
counter[d]++; // Count the occurrences of digit d
|
||||
}
|
||||
// Calculate prefix sum, converting "occurrence count" into "array index"
|
||||
// Compute prefix sums to convert occurrence counts into array positions
|
||||
for (int i = 1; i < 10; i++) {
|
||||
counter[i] += counter[i - 1];
|
||||
}
|
||||
// Traverse in reverse, based on bucket statistics, place each element into res
|
||||
// Traverse in reverse and place each element into res according to the bucket counts
|
||||
vector<int> res(n, 0);
|
||||
for (int i = n - 1; i >= 0; i--) {
|
||||
int d = digit(nums[i], exp);
|
||||
int j = counter[d] - 1; // Get the index j for d in the array
|
||||
int j = counter[d] - 1; // Get the destination index j for digit d in the array
|
||||
res[j] = nums[i]; // Place the current element at index j
|
||||
counter[d]--; // Decrease the count of d by 1
|
||||
counter[d]--; // Decrease the count for d by 1
|
||||
}
|
||||
// Use result to overwrite the original array nums
|
||||
// Overwrite the original array nums with the result
|
||||
for (int i = 0; i < n; i++)
|
||||
nums[i] = res[i];
|
||||
}
|
||||
|
||||
/* Radix sort */
|
||||
void radixSort(vector<int> &nums) {
|
||||
// Get the maximum element of the array, used to determine the maximum number of digits
|
||||
// Get the largest array element to determine the maximum number of digits
|
||||
int m = *max_element(nums.begin(), nums.end());
|
||||
// Traverse from the lowest to the highest digit
|
||||
// Process digits from least significant to most significant
|
||||
for (int exp = 1; exp <= m; exp *= 10)
|
||||
// Perform counting sort on the k-th digit of array elements
|
||||
// Apply counting sort to the k-th digit of the array elements
|
||||
// k = 1 -> exp = 1
|
||||
// k = 2 -> exp = 10
|
||||
// i.e., exp = 10^(k-1)
|
||||
// That is, exp = 10^(k-1)
|
||||
countingSortDigit(nums, exp);
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
/* Driver code */
|
||||
int main() {
|
||||
// Radix sort
|
||||
vector<int> nums = {10546151, 35663510, 42865989, 34862445, 81883077,
|
||||
88906420, 72429244, 30524779, 82060337, 63832996};
|
||||
radixSort(nums);
|
||||
cout << "After radix sort completes, nums = ";
|
||||
cout << "After radix sort, nums = ";
|
||||
printVector(nums);
|
||||
|
||||
return 0;
|
||||
|
||||
@@ -9,25 +9,25 @@
|
||||
/* Selection sort */
|
||||
void selectionSort(vector<int> &nums) {
|
||||
int n = nums.size();
|
||||
// Outer loop: unsorted interval is [i, n-1]
|
||||
// Outer loop: the unsorted range is [i, n-1]
|
||||
for (int i = 0; i < n - 1; i++) {
|
||||
// Inner loop: find the smallest element within the unsorted interval
|
||||
// Inner loop: find the smallest element in the unsorted range
|
||||
int k = i;
|
||||
for (int j = i + 1; j < n; j++) {
|
||||
if (nums[j] < nums[k])
|
||||
k = j; // Record the index of the smallest element
|
||||
}
|
||||
// Swap the smallest element with the first element of the unsorted interval
|
||||
// Swap the smallest element with the first element of the unsorted range
|
||||
swap(nums[i], nums[k]);
|
||||
}
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
/* Driver code */
|
||||
int main() {
|
||||
vector<int> nums = {4, 1, 3, 1, 5, 2};
|
||||
selectionSort(nums);
|
||||
|
||||
cout << "After selection sort completes, nums = ";
|
||||
cout << "After selection sort, nums = ";
|
||||
printVector(nums);
|
||||
|
||||
return 0;
|
||||
|
||||
Reference in New Issue
Block a user