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Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
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@@ -9,10 +9,10 @@ package chapter_backtracking;
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import java.util.*;
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public class n_queens {
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/* Backtracking algorithm: N queens */
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/* Backtracking: n-queens */
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public static void backtrack(int row, int n, List<List<String>> state, List<List<List<String>>> res,
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boolean[] cols, boolean[] diags1, boolean[] diags2) {
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// When all rows are placed, record the solution
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// Record a solution when a queen has been placed in every row
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if (row == n) {
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List<List<String>> copyState = new ArrayList<>();
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for (List<String> sRow : state) {
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@@ -21,28 +21,28 @@ public class n_queens {
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res.add(copyState);
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return;
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}
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// Traverse all columns
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// Iterate over all columns
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for (int col = 0; col < n; col++) {
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// Calculate the main diagonal and anti-diagonal corresponding to this cell
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// Calculate the main-diagonal and anti-diagonal indices for this square
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int diag1 = row - col + n - 1;
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int diag2 = row + col;
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// Pruning: do not allow queens to exist in the column, main diagonal, and anti-diagonal of this cell
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// Prune: the square must have no queen in its column, main diagonal, or anti-diagonal
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if (!cols[col] && !diags1[diag1] && !diags2[diag2]) {
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// Attempt: place the queen in this cell
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// Try: place a queen on this square
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state.get(row).set(col, "Q");
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cols[col] = diags1[diag1] = diags2[diag2] = true;
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// Place the next row
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// Place a queen in the next row
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backtrack(row + 1, n, state, res, cols, diags1, diags2);
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// Backtrack: restore this cell to an empty cell
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// Backtrack: restore this square to empty
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state.get(row).set(col, "#");
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cols[col] = diags1[diag1] = diags2[diag2] = false;
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}
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}
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}
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/* Solve N queens */
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/* Solve the n-queens problem */
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public static List<List<List<String>>> nQueens(int n) {
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// Initialize an n*n chessboard, where 'Q' represents a queen and '#' represents an empty cell
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// Initialize an n*n board, where 'Q' represents a queen and '#' represents an empty square
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List<List<String>> state = new ArrayList<>();
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for (int i = 0; i < n; i++) {
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List<String> row = new ArrayList<>();
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@@ -51,9 +51,9 @@ public class n_queens {
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}
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state.add(row);
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}
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boolean[] cols = new boolean[n]; // Record whether there is a queen in the column
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boolean[] diags1 = new boolean[2 * n - 1]; // Record whether there is a queen on the main diagonal
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boolean[] diags2 = new boolean[2 * n - 1]; // Record whether there is a queen on the anti-diagonal
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boolean[] cols = new boolean[n]; // Track whether a column contains a queen
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boolean[] diags1 = new boolean[2 * n - 1]; // Track whether a main diagonal contains a queen
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boolean[] diags2 = new boolean[2 * n - 1]; // Track whether an anti-diagonal contains a queen
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List<List<List<String>>> res = new ArrayList<>();
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backtrack(0, n, state, res, cols, diags1, diags2);
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@@ -65,8 +65,8 @@ public class n_queens {
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int n = 4;
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List<List<List<String>>> res = nQueens(n);
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System.out.println("Input board size is " + n);
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System.out.println("Total queen placement solutions: " + res.size() + "");
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System.out.println("Input board side length: " + n);
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System.out.println("There are " + res.size() + " queen placements");
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for (List<List<String>> state : res) {
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System.out.println("--------------------");
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for (List<String> row : state) {
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