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Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
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@@ -9,73 +9,73 @@ package chapter_dynamic_programming;
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import java.util.Arrays;
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public class edit_distance {
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/* Edit distance: Brute-force search */
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/* Edit distance: brute-force search */
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static int editDistanceDFS(String s, String t, int i, int j) {
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// If both s and t are empty, return 0
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// If the current prefixes of s and t are both empty, return 0
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if (i == 0 && j == 0)
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return 0;
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// If s is empty, return length of t
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// If the current prefix of s is empty, return j, the length of the current prefix of t
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if (i == 0)
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return j;
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// If t is empty, return length of s
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// If the current prefix of t is empty, return i, the length of the current prefix of s
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if (j == 0)
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return i;
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// If two characters are equal, skip both characters
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// If the two characters are equal, skip both of them
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if (s.charAt(i - 1) == t.charAt(j - 1))
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return editDistanceDFS(s, t, i - 1, j - 1);
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// Minimum edit steps = minimum edit steps of insert, delete, replace + 1
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// Minimum edits = the minimum among the insertion, deletion, and replacement subproblems + 1
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int insert = editDistanceDFS(s, t, i, j - 1);
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int delete = editDistanceDFS(s, t, i - 1, j);
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int replace = editDistanceDFS(s, t, i - 1, j - 1);
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// Return minimum edit steps
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// Return the minimum number of edits
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return Math.min(Math.min(insert, delete), replace) + 1;
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}
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/* Edit distance: Memoization search */
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/* Edit distance: memoized search */
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static int editDistanceDFSMem(String s, String t, int[][] mem, int i, int j) {
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// If both s and t are empty, return 0
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// If the current prefixes of s and t are both empty, return 0
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if (i == 0 && j == 0)
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return 0;
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// If s is empty, return length of t
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// If the current prefix of s is empty, return j, the length of the current prefix of t
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if (i == 0)
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return j;
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// If t is empty, return length of s
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// If the current prefix of t is empty, return i, the length of the current prefix of s
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if (j == 0)
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return i;
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// If there's a record, return it directly
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// If a result has already been recorded, return it directly
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if (mem[i][j] != -1)
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return mem[i][j];
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// If two characters are equal, skip both characters
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// If the two characters are equal, skip both of them
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if (s.charAt(i - 1) == t.charAt(j - 1))
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return editDistanceDFSMem(s, t, mem, i - 1, j - 1);
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// Minimum edit steps = minimum edit steps of insert, delete, replace + 1
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// Minimum edits = the minimum among the insertion, deletion, and replacement subproblems + 1
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int insert = editDistanceDFSMem(s, t, mem, i, j - 1);
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int delete = editDistanceDFSMem(s, t, mem, i - 1, j);
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int replace = editDistanceDFSMem(s, t, mem, i - 1, j - 1);
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// Record and return minimum edit steps
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// Record and return the minimum number of edits
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mem[i][j] = Math.min(Math.min(insert, delete), replace) + 1;
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return mem[i][j];
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}
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/* Edit distance: Dynamic programming */
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/* Edit distance: dynamic programming */
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static int editDistanceDP(String s, String t) {
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int n = s.length(), m = t.length();
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int[][] dp = new int[n + 1][m + 1];
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// State transition: first row and first column
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// State transitions: first row and first column
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for (int i = 1; i <= n; i++) {
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dp[i][0] = i;
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}
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for (int j = 1; j <= m; j++) {
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dp[0][j] = j;
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}
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// State transition: rest of the rows and columns
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// State transitions: remaining rows and columns
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= m; j++) {
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if (s.charAt(i - 1) == t.charAt(j - 1)) {
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// If two characters are equal, skip both characters
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// If the two characters are equal, skip both of them
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dp[i][j] = dp[i - 1][j - 1];
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} else {
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// Minimum edit steps = minimum edit steps of insert, delete, replace + 1
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// Minimum edits = the minimum among the insertion, deletion, and replacement subproblems + 1
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dp[i][j] = Math.min(Math.min(dp[i][j - 1], dp[i - 1][j]), dp[i - 1][j - 1]) + 1;
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}
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}
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@@ -83,30 +83,30 @@ public class edit_distance {
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return dp[n][m];
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}
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/* Edit distance: Space-optimized dynamic programming */
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/* Edit distance: space-optimized dynamic programming */
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static int editDistanceDPComp(String s, String t) {
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int n = s.length(), m = t.length();
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int[] dp = new int[m + 1];
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// State transition: first row
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// State transitions: first row
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for (int j = 1; j <= m; j++) {
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dp[j] = j;
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}
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// State transition: rest of the rows
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// State transitions: remaining rows
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for (int i = 1; i <= n; i++) {
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// State transition: first column
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// State transitions: first column
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int leftup = dp[0]; // Temporarily store dp[i-1, j-1]
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dp[0] = i;
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// State transition: rest of the columns
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// State transitions: remaining columns
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for (int j = 1; j <= m; j++) {
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int temp = dp[j];
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if (s.charAt(i - 1) == t.charAt(j - 1)) {
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// If two characters are equal, skip both characters
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// If the two characters are equal, skip both of them
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dp[j] = leftup;
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} else {
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// Minimum edit steps = minimum edit steps of insert, delete, replace + 1
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// Minimum edits = the minimum among the insertion, deletion, and replacement subproblems + 1
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dp[j] = Math.min(Math.min(dp[j - 1], dp[j]), leftup) + 1;
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}
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leftup = temp; // Update for next round's dp[i-1, j-1]
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leftup = temp; // Update to dp[i-1, j-1] for the next iteration
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}
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}
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return dp[m];
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@@ -119,21 +119,21 @@ public class edit_distance {
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// Brute-force search
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int res = editDistanceDFS(s, t, n, m);
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System.out.println("Changing " + s + " to " + t + " requires a minimum of " + res + " edits");
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System.out.println("Changing " + s + " to " + t + " requires at least " + res + " edits");
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// Memoization search
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// Memoized search
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int[][] mem = new int[n + 1][m + 1];
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for (int[] row : mem)
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Arrays.fill(row, -1);
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res = editDistanceDFSMem(s, t, mem, n, m);
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System.out.println("Changing " + s + " to " + t + " requires a minimum of " + res + " edits");
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System.out.println("Changing " + s + " to " + t + " requires at least " + res + " edits");
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// Dynamic programming
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res = editDistanceDP(s, t);
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System.out.println("Changing " + s + " to " + t + " requires a minimum of " + res + " edits");
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System.out.println("Changing " + s + " to " + t + " requires at least " + res + " edits");
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// Space-optimized dynamic programming
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res = editDistanceDPComp(s, t);
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System.out.println("Changing " + s + " to " + t + " requires a minimum of " + res + " edits");
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System.out.println("Changing " + s + " to " + t + " requires at least " + res + " edits");
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}
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}
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