mirror of
https://github.com/krahets/hello-algo.git
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Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
This commit is contained in:
@@ -6,9 +6,9 @@
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/* Bubble sort */
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function bubbleSort(nums) {
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// Outer loop: unsorted range is [0, i]
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// Outer loop: the unsorted range is [0, i]
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for (let i = nums.length - 1; i > 0; i--) {
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// Inner loop: swap the largest element in the unsorted range [0, i] to the rightmost end of that range
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// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
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for (let j = 0; j < i; j++) {
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if (nums[j] > nums[j + 1]) {
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// Swap nums[j] and nums[j + 1]
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@@ -20,30 +20,30 @@ function bubbleSort(nums) {
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}
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}
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/* Bubble sort (flag optimization) */
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/* Bubble sort (flag optimization)*/
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function bubbleSortWithFlag(nums) {
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// Outer loop: unsorted range is [0, i]
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// Outer loop: the unsorted range is [0, i]
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for (let i = nums.length - 1; i > 0; i--) {
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let flag = false; // Initialize flag
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// Inner loop: swap the largest element in the unsorted range [0, i] to the rightmost end of that range
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let flag = false; // Initialize the flag
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// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
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for (let j = 0; j < i; j++) {
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if (nums[j] > nums[j + 1]) {
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// Swap nums[j] and nums[j + 1]
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let tmp = nums[j];
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nums[j] = nums[j + 1];
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nums[j + 1] = tmp;
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flag = true; // Record element swap
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flag = true; // Record that a swap occurred
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}
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}
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if (!flag) break; // No elements were swapped in this round of "bubbling", exit directly
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if (!flag) break; // Exit immediately if this pass made no swaps
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}
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}
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/* Driver Code */
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/* Driver code */
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const nums = [4, 1, 3, 1, 5, 2];
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bubbleSort(nums);
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console.log('After bubble sort, nums =', nums);
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console.log('After bubble sort, array =', nums);
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const nums1 = [4, 1, 3, 1, 5, 2];
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bubbleSortWithFlag(nums1);
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console.log('After bubble sort, nums =', nums1);
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console.log('After bubble sort, array =', nums1);
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@@ -6,25 +6,25 @@
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/* Bucket sort */
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function bucketSort(nums) {
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// Initialize k = n/2 buckets, expected to allocate 2 elements per bucket
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// Initialize ceil(n/2) buckets, aiming for about 2 elements per bucket
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const k = nums.length / 2;
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const buckets = [];
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for (let i = 0; i < k; i++) {
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buckets.push([]);
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}
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// 1. Distribute array elements into various buckets
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// 1. Distribute the array elements among the buckets
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for (const num of nums) {
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// Input data range is [0, 1), use num * k to map to index range [0, k-1]
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// The input range is [0, 1); floor(num * k) maps values to indices from 0 to ceil(k)-1
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const i = Math.floor(num * k);
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// Add num to bucket i
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buckets[i].push(num);
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}
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// 2. Sort each bucket
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for (const bucket of buckets) {
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// Use built-in sorting function, can also replace with other sorting algorithms
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// Use the built-in sorting function, or replace it with another sorting algorithm
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bucket.sort((a, b) => a - b);
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}
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// 3. Traverse buckets to merge results
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// 3. Traverse the buckets to combine the results
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let i = 0;
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for (const bucket of buckets) {
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for (const num of bucket) {
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@@ -33,7 +33,7 @@ function bucketSort(nums) {
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}
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}
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/* Driver Code */
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/* Driver code */
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const nums = [0.49, 0.96, 0.82, 0.09, 0.57, 0.43, 0.91, 0.75, 0.15, 0.37];
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bucketSort(nums);
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console.log('After bucket sort, nums =', nums);
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@@ -5,17 +5,17 @@
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*/
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/* Counting sort */
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// Simple implementation, cannot be used for sorting objects
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// Simple implementation; cannot be used to sort objects
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function countingSortNaive(nums) {
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// 1. Count the maximum element m in the array
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// 1. Find the maximum array element m
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let m = Math.max(...nums);
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// 2. Count the occurrence of each number
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// counter[num] represents the occurrence of num
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// 2. Count the occurrences of each number
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// counter[num] is the number of occurrences of num
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const counter = new Array(m + 1).fill(0);
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for (const num of nums) {
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counter[num]++;
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}
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// 3. Traverse counter, filling each element back into the original array nums
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// 3. Traverse counter and fill the original array nums with the elements
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let i = 0;
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for (let num = 0; num < m + 1; num++) {
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for (let j = 0; j < counter[num]; j++, i++) {
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@@ -25,37 +25,37 @@ function countingSortNaive(nums) {
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}
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/* Counting sort */
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// Complete implementation, can sort objects and is a stable sort
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// Full implementation; stable and adaptable to sorting objects
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function countingSort(nums) {
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// 1. Count the maximum element m in the array
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// 1. Find the maximum array element m
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let m = Math.max(...nums);
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// 2. Count the occurrence of each number
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// counter[num] represents the occurrence of num
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// 2. Count the occurrences of each number
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// counter[num] is the number of occurrences of num
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const counter = new Array(m + 1).fill(0);
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for (const num of nums) {
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counter[num]++;
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}
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// 3. Calculate the prefix sum of counter, converting "occurrence count" to "tail index"
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// counter[num]-1 is the last index where num appears in res
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// 3. Compute prefix sums of counter to convert occurrence counts into end positions
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// That is, counter[num]-1 is the index of the last occurrence of num in res
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for (let i = 0; i < m; i++) {
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counter[i + 1] += counter[i];
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}
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// 4. Traverse nums in reverse order, placing each element into the result array res
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// Initialize the array res to record results
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// 4. Traverse nums in reverse and place each element in the result array res
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// Initialize array res to store the result
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const n = nums.length;
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const res = new Array(n);
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for (let i = n - 1; i >= 0; i--) {
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const num = nums[i];
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res[counter[num] - 1] = num; // Place num at the corresponding index
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counter[num]--; // Decrement the prefix sum by 1, getting the next index to place num
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counter[num]--; // Decrement the prefix sum by 1 to determine where to place the next occurrence of num
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}
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// Use result array res to overwrite the original array nums
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// Overwrite the original array nums with the result array res
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for (let i = 0; i < n; i++) {
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nums[i] = res[i];
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}
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}
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/* Driver Code */
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/* Driver code */
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const nums = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4];
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countingSortNaive(nums);
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console.log('After counting sort (cannot sort objects), nums =', nums);
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@@ -4,10 +4,10 @@
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* Author: Justin (xiefahit@gmail.com)
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*/
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/* Heap length is n, start heapifying node i, from top to bottom */
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/* Sift down from node i in a heap of size n */
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function siftDown(nums, n, i) {
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while (true) {
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// If node i is largest or indices l, r are out of bounds, no need to continue heapify, break
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// Find the node with the largest value among i, l, and r, and store its index in ma
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let l = 2 * i + 1;
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let r = 2 * i + 2;
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let ma = i;
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@@ -17,33 +17,33 @@ function siftDown(nums, n, i) {
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if (r < n && nums[r] > nums[ma]) {
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ma = r;
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}
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// Swap two nodes
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// Stop if node i is largest or both child indices l and r are out of bounds
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if (ma === i) {
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break;
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}
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// Swap two nodes
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// Swap the two nodes
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[nums[i], nums[ma]] = [nums[ma], nums[i]];
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// Loop downwards heapification
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// Continue sifting down
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i = ma;
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}
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}
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/* Heap sort */
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function heapSort(nums) {
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// Build heap operation: heapify all nodes except leaves
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// Build the heap by sifting down from every non-leaf node
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for (let i = Math.floor(nums.length / 2) - 1; i >= 0; i--) {
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siftDown(nums, nums.length, i);
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}
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// Extract the largest element from the heap and repeat for n-1 rounds
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// Extract the largest element from the heap, repeating for n-1 rounds
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for (let i = nums.length - 1; i > 0; i--) {
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// Delete node
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// Swap the root with the rightmost leaf on the last level (the first and last elements of the current heap)
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[nums[0], nums[i]] = [nums[i], nums[0]];
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// Start heapifying the root node, from top to bottom
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// Sift down starting at the root
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siftDown(nums, i, 0);
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}
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}
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/* Driver Code */
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/* Driver code */
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const nums = [4, 1, 3, 1, 5, 2];
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heapSort(nums);
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console.log('After heap sort, nums =', nums);
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@@ -6,20 +6,20 @@
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/* Insertion sort */
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function insertionSort(nums) {
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// Outer loop: sorted interval is [0, i-1]
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// Outer loop: the sorted range is [0, i-1]
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for (let i = 1; i < nums.length; i++) {
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let base = nums[i],
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j = i - 1;
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// Inner loop: insert base into the correct position within the sorted interval [0, i-1]
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// Inner loop: insert base at the correct position in the sorted range [0, i-1]
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while (j >= 0 && nums[j] > base) {
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nums[j + 1] = nums[j]; // Move nums[j] to the right by one position
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nums[j + 1] = nums[j]; // Shift nums[j] one position to the right
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j--;
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}
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nums[j + 1] = base; // Assign base to the correct position
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nums[j + 1] = base; // Place base at the correct position
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}
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}
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/* Driver Code */
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/* Driver code */
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const nums = [4, 1, 3, 1, 5, 2];
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insertionSort(nums);
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console.log('After insertion sort, nums =', nums);
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@@ -4,16 +4,16 @@
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* Author: IsChristina (christinaxia77@foxmail.com)
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*/
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/* Merge left subarray and right subarray */
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/* Merge the left and right subarrays */
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function merge(nums, left, mid, right) {
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// Left subarray interval is [left, mid], right subarray interval is [mid+1, right]
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// Create a temporary array tmp to store the merged results
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// The left subarray spans [left, mid], and the right subarray spans [mid+1, right]
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// Create a temporary array tmp to store the merged result
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const tmp = new Array(right - left + 1);
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// Initialize the start indices of the left and right subarrays
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// Initialize the starting indices of the left and right subarrays
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let i = left,
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j = mid + 1,
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k = 0;
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// While both subarrays still have elements, compare and copy the smaller element into the temporary array
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// While both subarrays have elements remaining, compare them and copy the smaller element into the temporary array
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while (i <= mid && j <= right) {
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if (nums[i] <= nums[j]) {
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tmp[k++] = nums[i++];
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@@ -28,7 +28,7 @@ function merge(nums, left, mid, right) {
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while (j <= right) {
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tmp[k++] = nums[j++];
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}
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// Copy the elements from the temporary array tmp back to the original array nums at the corresponding interval
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// Copy the elements of temporary array tmp back into the corresponding range of the original array nums
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for (k = 0; k < tmp.length; k++) {
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nums[left + k] = tmp[k];
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}
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@@ -36,17 +36,17 @@ function merge(nums, left, mid, right) {
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/* Merge sort */
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function mergeSort(nums, left, right) {
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// Termination condition
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if (left >= right) return; // Terminate recursion when subarray length is 1
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// Divide and conquer stage
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let mid = Math.floor(left + (right - left) / 2); // Calculate midpoint
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mergeSort(nums, left, mid); // Recursively process the left subarray
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mergeSort(nums, mid + 1, right); // Recursively process the right subarray
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// Merge stage
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// Base case
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if (left >= right) return; // Stop recursing when the subarray has at most one element
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// Divide phase
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let mid = Math.floor(left + (right - left) / 2); // Calculate the midpoint
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mergeSort(nums, left, mid); // Recurse on the left subarray
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mergeSort(nums, mid + 1, right); // Recurse on the right subarray
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// Merge phase
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merge(nums, left, mid, right);
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}
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/* Driver Code */
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/* Driver code */
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const nums = [7, 3, 2, 6, 0, 1, 5, 4];
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mergeSort(nums, 0, nums.length - 1);
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console.log('After merge sort, nums =', nums);
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@@ -6,39 +6,39 @@
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/* Quick sort class */
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class QuickSort {
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/* Swap elements */
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/* Swap the elements */
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swap(nums, i, j) {
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let tmp = nums[i];
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nums[i] = nums[j];
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nums[j] = tmp;
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}
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/* Sentinel partition */
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/* Two-pointer partitioning */
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partition(nums, left, right) {
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// Use nums[left] as the pivot
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let i = left,
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j = right;
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while (i < j) {
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while (i < j && nums[j] >= nums[left]) {
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j -= 1; // Search from right to left for the first element smaller than the pivot
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j -= 1; // Scan from right to left for the first element smaller than the pivot
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}
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while (i < j && nums[i] <= nums[left]) {
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i += 1; // Search from left to right for the first element greater than the pivot
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i += 1; // Scan from left to right for the first element larger than the pivot
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}
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// Swap elements
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// Swap the elements
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this.swap(nums, i, j); // Swap these two elements
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}
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this.swap(nums, i, left); // Swap the pivot to the boundary between the two subarrays
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return i; // Return the index of the pivot
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this.swap(nums, i, left); // Swap the pivot into the boundary position between the two subarrays
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return i; // Return the pivot index
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}
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/* Quick sort */
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quickSort(nums, left, right) {
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// Terminate recursion when subarray length is 1
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// Stop recursing when the subarray has at most one element
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if (left >= right) return;
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// Sentinel partition
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// Two-pointer partitioning
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const pivot = this.partition(nums, left, right);
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// Recursively process the left subarray and right subarray
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// Recurse on the left and right subarrays
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this.quickSort(nums, left, pivot - 1);
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this.quickSort(nums, pivot + 1, right);
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}
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@@ -46,7 +46,7 @@ class QuickSort {
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/* Quick sort class (median pivot optimization) */
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class QuickSortMedian {
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/* Swap elements */
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/* Swap the elements */
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swap(nums, i, j) {
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let tmp = nums[i];
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nums[i] = nums[j];
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@@ -58,14 +58,14 @@ class QuickSortMedian {
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let l = nums[left],
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m = nums[mid],
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r = nums[right];
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// m is between l and r
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// m lies between l and r
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if ((l <= m && m <= r) || (r <= m && m <= l)) return mid;
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// l is between m and r
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// l lies between m and r
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if ((m <= l && l <= r) || (r <= l && l <= m)) return left;
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return right;
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}
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/* Sentinel partition (median of three) */
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/* Two-pointer partitioning (median of three) */
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partition(nums, left, right) {
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// Select the median of three candidate elements
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let med = this.medianThree(
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@@ -74,27 +74,27 @@ class QuickSortMedian {
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Math.floor((left + right) / 2),
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right
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);
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// Swap the median to the array's leftmost position
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// Swap the median into the leftmost position of the current subarray
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this.swap(nums, left, med);
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// Use nums[left] as the pivot
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let i = left,
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j = right;
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while (i < j) {
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while (i < j && nums[j] >= nums[left]) j--; // Search from right to left for the first element smaller than the pivot
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while (i < j && nums[i] <= nums[left]) i++; // Search from left to right for the first element greater than the pivot
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while (i < j && nums[j] >= nums[left]) j--; // Scan from right to left for the first element smaller than the pivot
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while (i < j && nums[i] <= nums[left]) i++; // Scan from left to right for the first element larger than the pivot
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this.swap(nums, i, j); // Swap these two elements
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}
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this.swap(nums, i, left); // Swap the pivot to the boundary between the two subarrays
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return i; // Return the index of the pivot
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this.swap(nums, i, left); // Swap the pivot into the boundary position between the two subarrays
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return i; // Return the pivot index
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}
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/* Quick sort */
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quickSort(nums, left, right) {
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// Terminate recursion when subarray length is 1
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// Stop recursing when the subarray has at most one element
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if (left >= right) return;
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// Sentinel partition
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// Two-pointer partitioning
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const pivot = this.partition(nums, left, right);
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// Recursively process the left subarray and right subarray
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// Recurse on the left and right subarrays
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this.quickSort(nums, left, pivot - 1);
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this.quickSort(nums, pivot + 1, right);
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}
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@@ -102,60 +102,60 @@ class QuickSortMedian {
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/* Quick sort class (recursion depth optimization) */
|
||||
class QuickSortTailCall {
|
||||
/* Swap elements */
|
||||
/* Swap the elements */
|
||||
swap(nums, i, j) {
|
||||
let tmp = nums[i];
|
||||
nums[i] = nums[j];
|
||||
nums[j] = tmp;
|
||||
}
|
||||
|
||||
/* Sentinel partition */
|
||||
/* Two-pointer partitioning */
|
||||
partition(nums, left, right) {
|
||||
// Use nums[left] as the pivot
|
||||
let i = left,
|
||||
j = right;
|
||||
while (i < j) {
|
||||
while (i < j && nums[j] >= nums[left]) j--; // Search from right to left for the first element smaller than the pivot
|
||||
while (i < j && nums[i] <= nums[left]) i++; // Search from left to right for the first element greater than the pivot
|
||||
while (i < j && nums[j] >= nums[left]) j--; // Scan from right to left for the first element smaller than the pivot
|
||||
while (i < j && nums[i] <= nums[left]) i++; // Scan from left to right for the first element larger than the pivot
|
||||
this.swap(nums, i, j); // Swap these two elements
|
||||
}
|
||||
this.swap(nums, i, left); // Swap the pivot to the boundary between the two subarrays
|
||||
return i; // Return the index of the pivot
|
||||
this.swap(nums, i, left); // Swap the pivot into the boundary position between the two subarrays
|
||||
return i; // Return the pivot index
|
||||
}
|
||||
|
||||
/* Quick sort (recursion depth optimization) */
|
||||
quickSort(nums, left, right) {
|
||||
// Terminate when subarray length is 1
|
||||
// Stop when the subarray has at most one element
|
||||
while (left < right) {
|
||||
// Sentinel partition operation
|
||||
// Perform two-pointer partitioning
|
||||
let pivot = this.partition(nums, left, right);
|
||||
// Perform quick sort on the shorter of the two subarrays
|
||||
// Apply quick sort to the shorter of the two subarrays
|
||||
if (pivot - left < right - pivot) {
|
||||
this.quickSort(nums, left, pivot - 1); // Recursively sort the left subarray
|
||||
left = pivot + 1; // Remaining unsorted interval is [pivot + 1, right]
|
||||
left = pivot + 1; // The remaining unsorted range is [pivot + 1, right]
|
||||
} else {
|
||||
this.quickSort(nums, pivot + 1, right); // Recursively sort the right subarray
|
||||
right = pivot - 1; // Remaining unsorted interval is [left, pivot - 1]
|
||||
right = pivot - 1; // The remaining unsorted range is [left, pivot - 1]
|
||||
}
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
/* Quick sort */
|
||||
/* Driver code */
|
||||
/* Quick sort */
|
||||
const nums = [2, 4, 1, 0, 3, 5];
|
||||
const quickSort = new QuickSort();
|
||||
quickSort.quickSort(nums, 0, nums.length - 1);
|
||||
console.log('After quick sort, nums =', nums);
|
||||
|
||||
/* Quick sort (recursion depth optimization) */
|
||||
/* Quick sort (median pivot optimization) */
|
||||
const nums1 = [2, 4, 1, 0, 3, 5];
|
||||
const quickSortMedian = new QuickSortMedian();
|
||||
quickSortMedian.quickSort(nums1, 0, nums1.length - 1);
|
||||
console.log('After quick sort (median pivot optimization), nums =', nums1);
|
||||
console.log('After quick sort (median pivot optimization), nums1 =', nums1);
|
||||
|
||||
/* Quick sort (recursion depth optimization) */
|
||||
const nums2 = [2, 4, 1, 0, 3, 5];
|
||||
const quickSortTailCall = new QuickSortTailCall();
|
||||
quickSortTailCall.quickSort(nums2, 0, nums2.length - 1);
|
||||
console.log('After quick sort (recursion depth optimization), nums =', nums2);
|
||||
console.log('After quick sort (recursion depth optimization), nums2 =', nums2);
|
||||
|
||||
@@ -4,35 +4,35 @@
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* Get the k-th digit of element num, where exp = 10^(k-1) */
|
||||
/* Get the k-th digit of num, where exp = 10^(k-1) */
|
||||
function digit(num, exp) {
|
||||
// Passing exp instead of k can avoid repeated expensive exponentiation here
|
||||
// Passing exp instead of k avoids repeatedly performing expensive exponentiation here
|
||||
return Math.floor(num / exp) % 10;
|
||||
}
|
||||
|
||||
/* Counting sort (based on nums k-th digit) */
|
||||
/* Counting sort (sort nums by the k-th digit) */
|
||||
function countingSortDigit(nums, exp) {
|
||||
// Decimal digit range is 0~9, therefore need a bucket array of length 10
|
||||
// Decimal digits range from 0 to 9, so the bucket array needs length 10
|
||||
const counter = new Array(10).fill(0);
|
||||
const n = nums.length;
|
||||
// Count the occurrence of digits 0~9
|
||||
// Count the occurrences of each digit from 0 to 9
|
||||
for (let i = 0; i < n; i++) {
|
||||
const d = digit(nums[i], exp); // Get the k-th digit of nums[i], noted as d
|
||||
counter[d]++; // Count the occurrence of digit d
|
||||
const d = digit(nums[i], exp); // Get the k-th digit of nums[i] and store it in d
|
||||
counter[d]++; // Count the occurrences of digit d
|
||||
}
|
||||
// Calculate prefix sum, converting "occurrence count" into "array index"
|
||||
// Compute prefix sums to convert occurrence counts into array positions
|
||||
for (let i = 1; i < 10; i++) {
|
||||
counter[i] += counter[i - 1];
|
||||
}
|
||||
// Traverse in reverse, based on bucket statistics, place each element into res
|
||||
// Traverse in reverse and place each element into res according to the bucket counts
|
||||
const res = new Array(n).fill(0);
|
||||
for (let i = n - 1; i >= 0; i--) {
|
||||
const d = digit(nums[i], exp);
|
||||
const j = counter[d] - 1; // Get the index j for d in the array
|
||||
const j = counter[d] - 1; // Get the destination index j for digit d in the array
|
||||
res[j] = nums[i]; // Place the current element at index j
|
||||
counter[d]--; // Decrease the count of d by 1
|
||||
counter[d]--; // Decrease the count for d by 1
|
||||
}
|
||||
// Use result to overwrite the original array nums
|
||||
// Overwrite the original array nums with the result
|
||||
for (let i = 0; i < n; i++) {
|
||||
nums[i] = res[i];
|
||||
}
|
||||
@@ -40,19 +40,19 @@ function countingSortDigit(nums, exp) {
|
||||
|
||||
/* Radix sort */
|
||||
function radixSort(nums) {
|
||||
// Get the maximum element of the array, used to determine the maximum number of digits
|
||||
// Get the largest array element to determine the maximum number of digits
|
||||
let m = Math.max(... nums);
|
||||
// Traverse from the lowest to the highest digit
|
||||
// Process digits from least significant to most significant
|
||||
for (let exp = 1; exp <= m; exp *= 10) {
|
||||
// Perform counting sort on the k-th digit of array elements
|
||||
// Apply counting sort to the k-th digit of the array elements
|
||||
// k = 1 -> exp = 1
|
||||
// k = 2 -> exp = 10
|
||||
// i.e., exp = 10^(k-1)
|
||||
// That is, exp = 10^(k-1)
|
||||
countingSortDigit(nums, exp);
|
||||
}
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
/* Driver code */
|
||||
const nums = [
|
||||
10546151, 35663510, 42865989, 34862445, 81883077, 88906420, 72429244,
|
||||
30524779, 82060337, 63832996,
|
||||
|
||||
@@ -7,21 +7,21 @@
|
||||
/* Selection sort */
|
||||
function selectionSort(nums) {
|
||||
let n = nums.length;
|
||||
// Outer loop: unsorted interval is [i, n-1]
|
||||
// Outer loop: the unsorted range is [i, n-1]
|
||||
for (let i = 0; i < n - 1; i++) {
|
||||
// Inner loop: find the smallest element within the unsorted interval
|
||||
// Inner loop: find the smallest element in the unsorted range
|
||||
let k = i;
|
||||
for (let j = i + 1; j < n; j++) {
|
||||
if (nums[j] < nums[k]) {
|
||||
k = j; // Record the index of the smallest element
|
||||
}
|
||||
}
|
||||
// Swap the smallest element with the first element of the unsorted interval
|
||||
// Swap the smallest element with the first element of the unsorted range
|
||||
[nums[i], nums[k]] = [nums[k], nums[i]];
|
||||
}
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
/* Driver code */
|
||||
const nums = [4, 1, 3, 1, 5, 2];
|
||||
selectionSort(nums);
|
||||
console.log('After selection sort, nums =', nums);
|
||||
|
||||
Reference in New Issue
Block a user