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@@ -276,7 +276,20 @@ comments: true
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=== "Ruby"
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```ruby title="bubble_sort.rb"
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[class]{}-[func]{bubble_sort}
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### 冒泡排序 ###
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def bubble_sort(nums)
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n = nums.length
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# 外循环:未排序区间为 [0, i]
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for i in (n - 1).downto(1)
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# 内循环:将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
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for j in 0...i
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if nums[j] > nums[j + 1]
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# 交换 nums[j] 与 nums[j + 1]
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nums[j], nums[j + 1] = nums[j + 1], nums[j]
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end
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end
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end
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end
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```
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=== "Zig"
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@@ -587,7 +600,25 @@ comments: true
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=== "Ruby"
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```ruby title="bubble_sort.rb"
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[class]{}-[func]{bubble_sort_with_flag}
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### 冒泡排序(标志优化)###
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def bubble_sort_with_flag(nums)
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n = nums.length
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# 外循环:未排序区间为 [0, i]
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for i in (n - 1).downto(1)
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flag = false # 初始化标志位
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# 内循环:将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
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for j in 0...i
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if nums[j] > nums[j + 1]
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# 交换 nums[j] 与 nums[j + 1]
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nums[j], nums[j + 1] = nums[j + 1], nums[j]
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flag = true # 记录交换元素
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end
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end
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break unless flag # 此轮“冒泡”未交换任何元素,直接跳出
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end
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end
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```
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=== "Zig"
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@@ -348,7 +348,25 @@ comments: true
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=== "Ruby"
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```ruby title="counting_sort.rb"
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[class]{}-[func]{counting_sort_naive}
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### 计数排序 ###
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def counting_sort_naive(nums)
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# 简单实现,无法用于排序对象
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# 1. 统计数组最大元素 m
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m = 0
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nums.each { |num| m = [m, num].max }
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# 2. 统计各数字的出现次数
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# counter[num] 代表 num 的出现次数
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counter = Array.new(m + 1, 0)
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nums.each { |num| counter[num] += 1 }
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# 3. 遍历 counter ,将各元素填入原数组 nums
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i = 0
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for num in 0...(m + 1)
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(0...counter[num]).each do
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nums[i] = num
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i += 1
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end
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end
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end
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```
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=== "Zig"
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@@ -854,7 +872,30 @@ $$
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=== "Ruby"
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```ruby title="counting_sort.rb"
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[class]{}-[func]{counting_sort}
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### 计数排序 ###
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def counting_sort(nums)
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# 完整实现,可排序对象,并且是稳定排序
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# 1. 统计数组最大元素 m
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m = nums.max
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# 2. 统计各数字的出现次数
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# counter[num] 代表 num 的出现次数
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counter = Array.new(m + 1, 0)
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nums.each { |num| counter[num] += 1 }
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# 3. 求 counter 的前缀和,将“出现次数”转换为“尾索引”
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# 即 counter[num]-1 是 num 在 res 中最后一次出现的索引
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(0...m).each { |i| counter[i + 1] += counter[i] }
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# 4. 倒序遍历 nums, 将各元素填入结果数组 res
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# 初始化数组 res 用于记录结果
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n = nums.length
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res = Array.new(n, 0)
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(n - 1).downto(0).each do |i|
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num = nums[i]
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res[counter[num] - 1] = num # 将 num 放置到对应索引处
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counter[num] -= 1 # 令前缀和自减 1 ,得到下次放置 num 的索引
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end
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# 使用结果数组 res 覆盖原数组 nums
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(0...n).each { |i| nums[i] = res[i] }
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end
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```
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=== "Zig"
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@@ -353,7 +353,24 @@ comments: true
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=== "Ruby"
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```ruby title="quick_sort.rb"
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[class]{QuickSort}-[func]{partition}
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### 哨兵划分 ###
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def partition(nums, left, right)
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# 以 nums[left] 为基准数
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i, j = left, right
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while i < j
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while i < j && nums[j] >= nums[left]
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j -= 1 # 从右向左找首个小于基准数的元素
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end
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while i < j && nums[i] <= nums[left]
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i += 1 # 从左向右找首个大于基准数的元素
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end
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# 元素交换
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nums[i], nums[j] = nums[j], nums[i]
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end
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# 将基准数交换至两子数组的分界线
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nums[i], nums[left] = nums[left], nums[i]
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i # 返回基准数的索引
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end
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```
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=== "Zig"
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@@ -594,7 +611,18 @@ comments: true
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=== "Ruby"
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```ruby title="quick_sort.rb"
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[class]{QuickSort}-[func]{quick_sort}
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### 快速排序类 ###
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def quick_sort(nums, left, right)
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# 子数组长度不为 1 时递归
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if left < right
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# 哨兵划分
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pivot = partition(nums, left, right)
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# 递归左子数组、右子数组
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quick_sort(nums, left, pivot - 1)
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quick_sort(nums, pivot + 1, right)
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end
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nums
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end
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```
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=== "Zig"
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@@ -1067,9 +1095,38 @@ comments: true
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=== "Ruby"
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```ruby title="quick_sort.rb"
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[class]{QuickSortMedian}-[func]{median_three}
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### 选取三个候选元素的中位数 ###
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def median_three(nums, left, mid, right)
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# 选取三个候选元素的中位数
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_l, _m, _r = nums[left], nums[mid], nums[right]
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# m 在 l 和 r 之间
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return mid if (_l <= _m && _m <= _r) || (_r <= _m && _m <= _l)
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# l 在 m 和 r 之间
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return left if (_m <= _l && _l <= _r) || (_r <= _l && _l <= _m)
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return right
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end
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[class]{QuickSortMedian}-[func]{partition}
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### 哨兵划分(三数取中值)###
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def partition(nums, left, right)
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### 以 nums[left] 为基准数
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med = median_three(nums, left, (left + right) / 2, right)
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# 将中位数交换至数组最左断
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nums[left], nums[med] = nums[med], nums[left]
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i, j = left, right
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while i < j
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while i < j && nums[j] >= nums[left]
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j -= 1 # 从右向左找首个小于基准数的元素
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end
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while i < j && nums[i] <= nums[left]
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i += 1 # 从左向右找首个大于基准数的元素
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end
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# 元素交换
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nums[i], nums[j] = nums[j], nums[i]
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end
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# 将基准数交换至两子数组的分界线
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nums[i], nums[left] = nums[left], nums[i]
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i # 返回基准数的索引
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end
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```
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=== "Zig"
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@@ -1377,7 +1434,22 @@ comments: true
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=== "Ruby"
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```ruby title="quick_sort.rb"
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[class]{QuickSortTailCall}-[func]{quick_sort}
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### 快速排序(尾递归优化)###
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def quick_sort(nums, left, right)
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# 子数组长度不为 1 时递归
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while left < right
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# 哨兵划分
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pivot = partition(nums, left, right)
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# 对两个子数组中较短的那个执行快速排序
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if pivot - left < right - pivot
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quick_sort(nums, left, pivot - 1)
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left = pivot + 1 # 剩余未排序区间为 [pivot + 1, right]
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else
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quick_sort(nums, pivot + 1, right)
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right = pivot - 1 # 剩余未排序区间为 [left, pivot - 1]
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end
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end
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end
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```
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=== "Zig"
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@@ -677,11 +677,51 @@ $$
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=== "Ruby"
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```ruby title="radix_sort.rb"
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[class]{}-[func]{digit}
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### 获取元素 num 的第 k 位,其中 exp = 10^(k-1) ###
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def digit(num, exp)
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# 转入 exp 而非 k 可以避免在此重复执行昂贵的次方计算
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(num / exp) % 10
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end
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[class]{}-[func]{counting_sort_digit}
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### 计数排序(根据 nums 第 k 位排序)###
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def counting_sort_digit(nums, exp)
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# 十进制的位范围为 0~9 ,因此需要长度为 10 的桶数组
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counter = Array.new(10, 0)
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n = nums.length
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# 统计 0~9 各数字的出现次数
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for i in 0...n
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d = digit(nums[i], exp) # 获取 nums[i] 第 k 位,记为 d
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counter[d] += 1 # 统计数字 d 的出现次数
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end
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# 求前缀和,将“出现个数”转换为“数组索引”
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(1...10).each { |i| counter[i] += counter[i - 1] }
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# 倒序遍历,根据桶内统计结果,将各元素填入 res
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res = Array.new(n, 0)
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for i in (n - 1).downto(0)
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d = digit(nums[i], exp)
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j = counter[d] - 1 # 获取 d 在数组中的索引 j
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res[j] = nums[i] # 将当前元素填入索引 j
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counter[d] -= 1 # 将 d 的数量减 1
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end
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# 使用结果覆盖原数组 nums
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(0...n).each { |i| nums[i] = res[i] }
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end
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[class]{}-[func]{radix_sort}
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### 基数排序 ###
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def radix_sort(nums)
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# 获取数组的最大元素,用于判断最大位数
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m = nums.max
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# 按照从低位到高位的顺序遍历
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exp = 1
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while exp <= m
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# 对数组元素的第 k 位执行计数排序
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# k = 1 -> exp = 1
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# k = 2 -> exp = 10
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# 即 exp = 10^(k-1)
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counting_sort_digit(nums, exp)
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exp *= 10
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end
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end
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```
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=== "Zig"
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@@ -306,7 +306,22 @@ comments: true
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=== "Ruby"
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```ruby title="selection_sort.rb"
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[class]{}-[func]{selection_sort}
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### 选择排序 ###
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def selection_sort(nums)
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n = nums.length
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# 外循环:未排序区间为 [i, n-1]
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for i in 0...(n - 1)
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# 内循环:找到未排序区间内的最小元素
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k = i
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for j in (i + 1)...n
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if nums[j] < nums[k]
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k = j # 记录最小元素的索引
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end
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end
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# 将该最小元素与未排序区间的首个元素交换
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nums[i], nums[k] = nums[k], nums[i]
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end
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end
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```
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=== "Zig"
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