mirror of
https://github.com/krahets/hello-algo.git
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Translate all code to English (#1836)
* Review the EN heading format. * Fix pythontutor headings. * Fix pythontutor headings. * bug fixes * Fix headings in **/summary.md * Revisit the CN-to-EN translation for Python code using Claude-4.5 * Revisit the CN-to-EN translation for Java code using Claude-4.5 * Revisit the CN-to-EN translation for Cpp code using Claude-4.5. * Fix the dictionary. * Fix cpp code translation for the multipart strings. * Translate Go code to English. * Update workflows to test EN code. * Add EN translation for C. * Add EN translation for CSharp. * Add EN translation for Swift. * Trigger the CI check. * Revert. * Update en/hash_map.md * Add the EN version of Dart code. * Add the EN version of Kotlin code. * Add missing code files. * Add the EN version of JavaScript code. * Add the EN version of TypeScript code. * Fix the workflows. * Add the EN version of Ruby code. * Add the EN version of Rust code. * Update the CI check for the English version code. * Update Python CI check. * Fix cmakelists for en/C code. * Fix Ruby comments
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@@ -6,14 +6,14 @@
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#include "../utils/common.hpp"
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/* Coin change: Greedy */
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/* Coin change: Greedy algorithm */
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int coinChangeGreedy(vector<int> &coins, int amt) {
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// Assume coins list is ordered
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// Assume coins list is sorted
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int i = coins.size() - 1;
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int count = 0;
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// Loop for greedy selection until no remaining amount
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// Loop to make greedy choices until no remaining amount
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while (amt > 0) {
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// Find the smallest coin close to and less than the remaining amount
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// Find the coin that is less than and closest to the remaining amount
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while (i > 0 && coins[i] > amt) {
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i--;
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}
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@@ -27,34 +27,34 @@ int coinChangeGreedy(vector<int> &coins, int amt) {
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/* Driver Code */
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int main() {
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// Greedy: can ensure finding a global optimal solution
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// Greedy algorithm: Can guarantee finding the global optimal solution
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vector<int> coins = {1, 5, 10, 20, 50, 100};
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int amt = 186;
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int res = coinChangeGreedy(coins, amt);
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cout << "\ncoins = ";
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printVector(coins);
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cout << "amt = " << amt << endl;
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cout << "The minimum number of coins required to make up " << amt << " is " << res << endl;
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cout << "Minimum number of coins needed to make " << amt << " is " << res << endl;
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// Greedy: cannot ensure finding a global optimal solution
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// Greedy algorithm: Cannot guarantee finding the global optimal solution
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coins = {1, 20, 50};
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amt = 60;
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res = coinChangeGreedy(coins, amt);
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cout << "\ncoins = ";
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printVector(coins);
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cout << "amt = " << amt << endl;
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cout << "The minimum number of coins required to make up " << amt << " is " << res << endl;
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cout << "In reality, the minimum number needed is 3, i.e., 20 + 20 + 20" << endl;
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cout << "Minimum number of coins needed to make " << amt << " is " << res << endl;
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cout << "Actually the minimum number needed is 3, i.e., 20 + 20 + 20" << endl;
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// Greedy: cannot ensure finding a global optimal solution
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// Greedy algorithm: Cannot guarantee finding the global optimal solution
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coins = {1, 49, 50};
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amt = 98;
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res = coinChangeGreedy(coins, amt);
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cout << "\ncoins = ";
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printVector(coins);
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cout << "amt = " << amt << endl;
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cout << "The minimum number of coins required to make up " << amt << " is " << res << endl;
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cout << "In reality, the minimum number needed is 2, i.e., 49 + 49" << endl;
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cout << "Minimum number of coins needed to make " << amt << " is " << res << endl;
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cout << "Actually the minimum number needed is 2, i.e., 49 + 49" << endl;
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return 0;
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}
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@@ -16,9 +16,9 @@ class Item {
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}
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};
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/* Fractional knapsack: Greedy */
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/* Fractional knapsack: Greedy algorithm */
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double fractionalKnapsack(vector<int> &wgt, vector<int> &val, int cap) {
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// Create an item list, containing two properties: weight, value
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// Create item list with two attributes: weight, value
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vector<Item> items;
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for (int i = 0; i < wgt.size(); i++) {
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items.push_back(Item(wgt[i], val[i]));
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@@ -29,13 +29,13 @@ double fractionalKnapsack(vector<int> &wgt, vector<int> &val, int cap) {
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double res = 0;
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for (auto &item : items) {
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if (item.w <= cap) {
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// If the remaining capacity is sufficient, put the entire item into the knapsack
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// If remaining capacity is sufficient, put the entire current item into the knapsack
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res += item.v;
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cap -= item.w;
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} else {
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// If the remaining capacity is insufficient, put part of the item into the knapsack
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// If remaining capacity is insufficient, put part of the current item into the knapsack
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res += (double)item.v / item.w * cap;
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// No remaining capacity left, thus break the loop
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// No remaining capacity, so break out of the loop
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break;
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}
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}
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@@ -50,7 +50,7 @@ int main() {
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// Greedy algorithm
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double res = fractionalKnapsack(wgt, val, cap);
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cout << "The maximum value within the bag capacity is " << res << endl;
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cout << "Maximum item value not exceeding knapsack capacity is " << res << endl;
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return 0;
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}
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@@ -6,15 +6,15 @@
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#include "../utils/common.hpp"
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/* Maximum capacity: Greedy */
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/* Max capacity: Greedy algorithm */
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int maxCapacity(vector<int> &ht) {
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// Initialize i, j, making them split the array at both ends
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// Initialize i, j to be at both ends of the array
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int i = 0, j = ht.size() - 1;
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// Initial maximum capacity is 0
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// Initial max capacity is 0
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int res = 0;
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// Loop for greedy selection until the two boards meet
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while (i < j) {
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// Update maximum capacity
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// Update max capacity
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int cap = min(ht[i], ht[j]) * (j - i);
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res = max(res, cap);
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// Move the shorter board inward
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@@ -33,7 +33,7 @@ int main() {
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// Greedy algorithm
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int res = maxCapacity(ht);
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cout << "The maximum capacity is " << res << endl;
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cout << "Maximum capacity is " << res << endl;
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return 0;
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}
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@@ -6,17 +6,17 @@
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#include "../utils/common.hpp"
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/* Maximum product of cutting: Greedy */
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/* Max product cutting: Greedy algorithm */
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int maxProductCutting(int n) {
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// When n <= 3, must cut out a 1
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if (n <= 3) {
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return 1 * (n - 1);
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}
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// Greedy cut out 3s, a is the number of 3s, b is the remainder
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// Greedily cut out 3, a is the number of 3s, b is the remainder
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int a = n / 3;
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int b = n % 3;
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if (b == 1) {
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// When the remainder is 1, convert a pair of 1 * 3 into 2 * 2
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// When the remainder is 1, convert a pair of 1 * 3 to 2 * 2
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return (int)pow(3, a - 1) * 2 * 2;
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}
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if (b == 2) {
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