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Translate all code to English (#1836)
* Review the EN heading format. * Fix pythontutor headings. * Fix pythontutor headings. * bug fixes * Fix headings in **/summary.md * Revisit the CN-to-EN translation for Python code using Claude-4.5 * Revisit the CN-to-EN translation for Java code using Claude-4.5 * Revisit the CN-to-EN translation for Cpp code using Claude-4.5. * Fix the dictionary. * Fix cpp code translation for the multipart strings. * Translate Go code to English. * Update workflows to test EN code. * Add EN translation for C. * Add EN translation for CSharp. * Add EN translation for Swift. * Trigger the CI check. * Revert. * Update en/hash_map.md * Add the EN version of Dart code. * Add the EN version of Kotlin code. * Add missing code files. * Add the EN version of JavaScript code. * Add the EN version of TypeScript code. * Fix the workflows. * Add the EN version of Ruby code. * Add the EN version of Rust code. * Update the CI check for the English version code. * Update Python CI check. * Fix cmakelists for en/C code. * Fix Ruby comments
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@@ -10,17 +10,17 @@ import utils.*;
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import java.util.*;
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public class top_k {
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/* Using heap to find the largest k elements in an array */
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/* Find the largest k elements in array based on heap */
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static Queue<Integer> topKHeap(int[] nums, int k) {
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// Initialize min-heap
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// Python's heapq module implements min heap by default
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Queue<Integer> heap = new PriorityQueue<Integer>();
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// Enter the first k elements of the array into the heap
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// Enter the first k elements of array into heap
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for (int i = 0; i < k; i++) {
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heap.offer(nums[i]);
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}
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// From the k+1th element, keep the heap length as k
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// Starting from the (k+1)th element, maintain heap length as k
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for (int i = k; i < nums.length; i++) {
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// If the current element is larger than the heap top element, remove the heap top element and enter the current element into the heap
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// If current element is greater than top element, top element exits heap, current element enters heap
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if (nums[i] > heap.peek()) {
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heap.poll();
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heap.offer(nums[i]);
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