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krahets
2023-09-02 16:10:39 +08:00
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<p>假设元素两两之间互不相同,则 <span class="arithmatex">\(n\)</span> 个元素共有 <span class="arithmatex">\(n!\)</span> 种排列(阶乘);在记录结果时,需要复制长度为 <span class="arithmatex">\(n\)</span> 的列表,使用 <span class="arithmatex">\(O(n)\)</span> 时间。因此,<strong>时间复杂度为 <span class="arithmatex">\(O(n!n)\)</span></strong></p>
<p>假设元素两两之间互不相同,则 <span class="arithmatex">\(n\)</span> 个元素共有 <span class="arithmatex">\(n!\)</span> 种排列(阶乘);在记录结果时,需要复制长度为 <span class="arithmatex">\(n\)</span> 的列表,使用 <span class="arithmatex">\(O(n)\)</span> 时间。<strong>因此时间复杂度为 <span class="arithmatex">\(O(n!n)\)</span></strong></p>
<p>最大递归深度为 <span class="arithmatex">\(n\)</span> ,使用 <span class="arithmatex">\(O(n)\)</span> 栈帧空间。<code>selected</code> 使用 <span class="arithmatex">\(O(n)\)</span> 空间。同一时刻最多共有 <span class="arithmatex">\(n\)</span><code>duplicated</code> ,使用 <span class="arithmatex">\(O(n^2)\)</span> 空间。<strong>因此空间复杂度为 <span class="arithmatex">\(O(n^2)\)</span></strong></p>
<h3 id="3">3. &nbsp; 两种剪枝对比<a class="headerlink" href="#3" title="Permanent link">&para;</a></h3>
<p>请注意,虽然 <code>selected</code><code>duplicated</code> 都用作剪枝,但两者的目标是不同的。</p>