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第 12 章 分治
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第 15 章 贪心
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<p>向以上代码输入数组 <span class="arithmatex">\([3, 4, 5]\)</span> 和目标元素 <span class="arithmatex">\(9\)</span> ,输出结果为 <span class="arithmatex">\([3, 3, 3], [4, 5], [5, 4]\)</span> 。<strong>虽然成功找出了所有和为 <span class="arithmatex">\(9\)</span> 的子集,但其中存在重复的子集 <span class="arithmatex">\([4, 5]\)</span> 和 <span class="arithmatex">\([5, 4]\)</span></strong> 。</p>
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<p>这是因为搜索过程是区分选择顺序的,然而子集不区分选择顺序。如图 13-10 所示,先选 <span class="arithmatex">\(4\)</span> 后选 <span class="arithmatex">\(5\)</span> 与先选 <span class="arithmatex">\(5\)</span> 后选 <span class="arithmatex">\(4\)</span> 是两个不同的分支,但两者对应同一个子集。</p>
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<p><img alt="子集搜索与越界剪枝" src="../subset_sum_problem.assets/subset_sum_i_naive.png" /></p>
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<p><a class="glightbox" href="../subset_sum_problem.assets/subset_sum_i_naive.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="子集搜索与越界剪枝" src="../subset_sum_problem.assets/subset_sum_i_naive.png" /></a></p>
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<p align="center"> 图 13-10 子集搜索与越界剪枝 </p>
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<p>为了去除重复子集,<strong>一种直接的思路是对结果列表进行去重</strong>。但这个方法效率很低,有两方面原因。</p>
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<li>前两轮选择 <span class="arithmatex">\(4\)</span> 和 <span class="arithmatex">\(5\)</span> ,生成子集 <span class="arithmatex">\([4, 5, \dots]\)</span> 。</li>
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<li>若第一轮选择 <span class="arithmatex">\(5\)</span> ,<strong>则第二轮应该跳过 <span class="arithmatex">\(3\)</span> 和 <span class="arithmatex">\(4\)</span></strong> ,因为子集 <span class="arithmatex">\([5, 3, \dots]\)</span> 和 <span class="arithmatex">\([5, 4, \dots]\)</span> 与第 <code>1.</code> 和 <code>2.</code> 步中描述的子集完全重复。</li>
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<p><img alt="不同选择顺序导致的重复子集" src="../subset_sum_problem.assets/subset_sum_i_pruning.png" /></p>
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<p><a class="glightbox" href="../subset_sum_problem.assets/subset_sum_i_pruning.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="不同选择顺序导致的重复子集" src="../subset_sum_problem.assets/subset_sum_i_pruning.png" /></a></p>
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<p align="center"> 图 13-11 不同选择顺序导致的重复子集 </p>
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<p>总结来看,给定输入数组 <span class="arithmatex">\([x_1, x_2, \dots, x_n]\)</span> ,设搜索过程中的选择序列为 <span class="arithmatex">\([x_{i_1}, x_{i_2}, \dots, x_{i_m}]\)</span> ,则该选择序列需要满足 <span class="arithmatex">\(i_1 \leq i_2 \leq \dots \leq i_m\)</span> ,<strong>不满足该条件的选择序列都会造成重复,应当剪枝</strong>。</p>
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<p>如图 13-12 所示,为将数组 <span class="arithmatex">\([3, 4, 5]\)</span> 和目标元素 <span class="arithmatex">\(9\)</span> 输入到以上代码后的整体回溯过程。</p>
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<p><img alt="子集和 I 回溯过程" src="../subset_sum_problem.assets/subset_sum_i.png" /></p>
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<p><a class="glightbox" href="../subset_sum_problem.assets/subset_sum_i.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="子集和 I 回溯过程" src="../subset_sum_problem.assets/subset_sum_i.png" /></a></p>
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<p align="center"> 图 13-12 子集和 I 回溯过程 </p>
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<h2 id="1332">13.3.2 考虑重复元素的情况<a class="headerlink" href="#1332" title="Permanent link">¶</a></h2>
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<p>相比于上题,<strong>本题的输入数组可能包含重复元素</strong>,这引入了新的问题。例如,给定数组 <span class="arithmatex">\([4, \hat{4}, 5]\)</span> 和目标元素 <span class="arithmatex">\(9\)</span> ,则现有代码的输出结果为 <span class="arithmatex">\([4, 5], [\hat{4}, 5]\)</span> ,出现了重复子集。</p>
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<p><strong>造成这种重复的原因是相等元素在某轮中被多次选择</strong>。在图 13-13 中,第一轮共有三个选择,其中两个都为 <span class="arithmatex">\(4\)</span> ,会产生两个重复的搜索分支,从而输出重复子集;同理,第二轮的两个 <span class="arithmatex">\(4\)</span> 也会产生重复子集。</p>
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<p><img alt="相等元素导致的重复子集" src="../subset_sum_problem.assets/subset_sum_ii_repeat.png" /></p>
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<p><a class="glightbox" href="../subset_sum_problem.assets/subset_sum_ii_repeat.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="相等元素导致的重复子集" src="../subset_sum_problem.assets/subset_sum_ii_repeat.png" /></a></p>
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<p align="center"> 图 13-13 相等元素导致的重复子集 </p>
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<h3 id="1_1">1. 相等元素剪枝<a class="headerlink" href="#1_1" title="Permanent link">¶</a></h3>
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<p>图 13-14 展示了数组 <span class="arithmatex">\([4, 4, 5]\)</span> 和目标元素 <span class="arithmatex">\(9\)</span> 的回溯过程,共包含四种剪枝操作。请你将图示与代码注释相结合,理解整个搜索过程,以及每种剪枝操作是如何工作的。</p>
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<p><img alt="子集和 II 回溯过程" src="../subset_sum_problem.assets/subset_sum_ii.png" /></p>
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<p><a class="glightbox" href="../subset_sum_problem.assets/subset_sum_ii.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="子集和 II 回溯过程" src="../subset_sum_problem.assets/subset_sum_ii.png" /></a></p>
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<p align="center"> 图 13-14 子集和 II 回溯过程 </p>
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