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krahets
2023-07-26 15:34:59 +08:00
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<p>值得注意的是,由于 <span class="arithmatex">\(i\)</span><span class="arithmatex">\(j\)</span> 都是 <code>int</code> 类型,<strong>因此 <span class="arithmatex">\(i + j\)</span> 可能会超出 <code>int</code> 类型的取值范围</strong>。为了避免大数越界,我们通常采用公式 <span class="arithmatex">\(m = \lfloor {i + (j - i) / 2} \rfloor\)</span> 来计算中点。</p>
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<div class="highlight"><span class="filename">binary_search.java</span><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="cm">/* 二分查找(双闭区间) */</span>
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<h2 id="1011">10.1.1. &nbsp; 区间表示方法<a class="headerlink" href="#1011" title="Permanent link">&para;</a></h2>
<p>除了上述的双闭区间外,常见的区间表示还有“左闭右开”区间,定义为 <span class="arithmatex">\([0, n)\)</span> ,即左边界包含自身,右边界不包含自身。在该表示下,区间 <span class="arithmatex">\([i, j]\)</span><span class="arithmatex">\(i = j\)</span> 时为空。</p>
<p>我们可以基于该表示实现具有相同功能的二分查找算法。</p>
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<div class="highlight"><span class="filename">binary_search.java</span><pre><span></span><code><a id="__codelineno-12-1" name="__codelineno-12-1" href="#__codelineno-12-1"></a><span class="cm">/* 二分查找(左闭右开) */</span>

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<p>注意,数组可能不包含目标元素 <code>target</code> 。因此在函数返回前,我们需要先判断 <code>nums[i]</code><code>target</code> 是否相等,以及索引 <span class="arithmatex">\(i\)</span> 是否越界。</p>
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<div class="tabbed-set tabbed-alternate" data-tabs="2:12"><input checked="checked" id="__tabbed_2_1" name="__tabbed_2" type="radio" /><input id="__tabbed_2_2" name="__tabbed_2" type="radio" /><input id="__tabbed_2_3" name="__tabbed_2" type="radio" /><input id="__tabbed_2_4" name="__tabbed_2" type="radio" /><input id="__tabbed_2_5" name="__tabbed_2" type="radio" /><input id="__tabbed_2_6" name="__tabbed_2" type="radio" /><input id="__tabbed_2_7" name="__tabbed_2" type="radio" /><input id="__tabbed_2_8" name="__tabbed_2" type="radio" /><input id="__tabbed_2_9" name="__tabbed_2" type="radio" /><input id="__tabbed_2_10" name="__tabbed_2" type="radio" /><input id="__tabbed_2_11" name="__tabbed_2" type="radio" /><input id="__tabbed_2_12" name="__tabbed_2" type="radio" /><div class="tabbed-labels"><label for="__tabbed_2_1">Java</label><label for="__tabbed_2_2">C++</label><label for="__tabbed_2_3">Python</label><label for="__tabbed_2_4">Go</label><label for="__tabbed_2_5">JS</label><label for="__tabbed_2_6">TS</label><label for="__tabbed_2_7">C</label><label for="__tabbed_2_8">C#</label><label for="__tabbed_2_9">Swift</label><label for="__tabbed_2_10">Zig</label><label for="__tabbed_2_11">Dart</label><label for="__tabbed_2_12">Rust</label></div>
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<div class="highlight"><span class="filename">binary_search_edge.java</span><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="cm">/* 二分查找最左一个元素 */</span>
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<h2 id="1023">10.2.3. &nbsp; 查找右边界<a class="headerlink" href="#1023" title="Permanent link">&para;</a></h2>
<p>类似地,我们也可以二分查找最右边的 <code>target</code> 。当 <code>nums[m] == target</code> 时,说明大于 <code>target</code> 的元素在区间 <span class="arithmatex">\([m + 1, j]\)</span> 中,因此执行 <code>i = m + 1</code> <strong>使得指针 <span class="arithmatex">\(i\)</span> 向大于 <code>target</code> 的元素靠近</strong></p>
<p>完成二分后,<strong><span class="arithmatex">\(i\)</span> 指向首个大于 <code>target</code> 的元素,<span class="arithmatex">\(j\)</span> 指向最右边的 <code>target</code></strong> ,因此返回索引 <span class="arithmatex">\(j\)</span> 即可。</p>
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<div class="highlight"><span class="filename">binary_search_edge.java</span><pre><span></span><code><a id="__codelineno-12-1" name="__codelineno-12-1" href="#__codelineno-12-1"></a><span class="cm">/* 二分查找最右一个元素 */</span>

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<p><img alt="线性查找求解两数之和" src="../replace_linear_by_hashing.assets/two_sum_brute_force.png" /></p>
<p align="center"> Fig. 线性查找求解两数之和 </p>
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<div class="highlight"><span class="filename">two_sum.java</span><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="cm">/* 方法一:暴力枚举 */</span>
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<p>实现代码如下所示,仅需单层循环即可。</p>
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<div class="highlight"><span class="filename">two_sum.java</span><pre><span></span><code><a id="__codelineno-12-1" name="__codelineno-12-1" href="#__codelineno-12-1"></a><span class="cm">/* 方法二:辅助哈希表 */</span>