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feat: Revised the book (#978)

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* Sync recent changes to the revised Word.

* Revised the preface chapter

* Revised the introduction chapter

* Revised the computation complexity chapter

* Revised the chapter data structure

* Revised the chapter array and linked list

* Revised the chapter stack and queue

* Revised the chapter hashing

* Revised the chapter tree

* Revised the chapter heap

* Revised the chapter graph

* Revised the chapter searching

* Reivised the sorting chapter

* Revised the divide and conquer chapter

* Revised the chapter backtacking

* Revised the DP chapter

* Revised the greedy chapter

* Revised the appendix chapter

* Revised the preface chapter doubly

* Revised the figures
This commit is contained in:
Yudong Jin
2023-12-02 06:21:34 +08:00
committed by GitHub
parent b824d149cb
commit e720aa2d24
404 changed files with 1537 additions and 1558 deletions
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2
codes/c/chapter_dynamic_programming/climbing_stairs_backtrack.c
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@@ -25,7 +25,7 @@ void backtrack(int *choices, int state, int n, int *res, int len) {
/* 爬楼梯：回溯 */
int climbingStairsBacktrack(int n) {
int choices[2] = {1, 2}; // 可选择向上爬 1 或 2 阶
int choices[2] = {1, 2}; // 可选择向上爬 1 阶或 2 阶
int state = 0; // 从第 0 阶开始爬
int *res = (int *)malloc(sizeof(int));
*res = 0; // 使用 res[0] 记录方案数量

2
codes/c/chapter_dynamic_programming/coin_change.c
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@@ -24,7 +24,7 @@ int coinChangeDP(int coins[], int amt, int coinsSize) {
for (int a = 1; a <= amt; a++) {
dp[0][a] = MAX;
}
// 状态转移：其余行列
// 状态转移：其余行和列
for (int i = 1; i <= n; i++) {
for (int a = 1; a <= amt; a++) {
if (coins[i - 1] > a) {

2
codes/c/chapter_dynamic_programming/edit_distance.c
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@@ -72,7 +72,7 @@ int editDistanceDP(char *s, char *t, int n, int m) {
for (int j = 1; j <= m; j++) {
dp[0][j] = j;
}
// 状态转移：其余行列
// 状态转移：其余行和列
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (s[i - 1] == t[j - 1]) {

8
codes/c/chapter_dynamic_programming/knapsack.c
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@@ -13,11 +13,11 @@ int myMax(int a, int b) {
/* 0-1 背包：暴力搜索 */
int knapsackDFS(int wgt[], int val[], int i, int c) {
// 若已选完所有物品或背包无容量，则返回价值 0
// 若已选完所有物品或背包无剩余容量，则返回价值 0
if (i == 0 || c == 0) {
return 0;
}
// 若超过背包容量，则只能不放入背包
// 若超过背包容量，则只能选择不放入背包
if (wgt[i - 1] > c) {
return knapsackDFS(wgt, val, i - 1, c);
}
@@ -30,7 +30,7 @@ int knapsackDFS(int wgt[], int val[], int i, int c) {
/* 0-1 背包：记忆化搜索 */
int knapsackDFSMem(int wgt[], int val[], int memCols, int **mem, int i, int c) {
// 若已选完所有物品或背包无容量，则返回价值 0
// 若已选完所有物品或背包无剩余容量，则返回价值 0
if (i == 0 || c == 0) {
return 0;
}
@@ -38,7 +38,7 @@ int knapsackDFSMem(int wgt[], int val[], int memCols, int **mem, int i, int c) {
if (mem[i][c] != -1) {
return mem[i][c];
}
// 若超过背包容量，则只能不放入背包
// 若超过背包容量，则只能选择不放入背包
if (wgt[i - 1] > c) {
return knapsackDFSMem(wgt, val, memCols, mem, i - 1, c);
}

2
codes/c/chapter_dynamic_programming/min_path_sum.c
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@@ -69,7 +69,7 @@ int minPathSumDP(int grid[MAX_SIZE][MAX_SIZE], int n, int m) {
for (int i = 1; i < n; i++) {
dp[i][0] = dp[i - 1][0] + grid[i][0];
}
// 状态转移：其余行列
// 状态转移：其余行和列
for (int i = 1; i < n; i++) {
for (int j = 1; j < m; j++) {
dp[i][j] = myMin(dp[i][j - 1], dp[i - 1][j]) + grid[i][j];