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feat: Revised the book (#978)
* Sync recent changes to the revised Word. * Revised the preface chapter * Revised the introduction chapter * Revised the computation complexity chapter * Revised the chapter data structure * Revised the chapter array and linked list * Revised the chapter stack and queue * Revised the chapter hashing * Revised the chapter tree * Revised the chapter heap * Revised the chapter graph * Revised the chapter searching * Reivised the sorting chapter * Revised the divide and conquer chapter * Revised the chapter backtacking * Revised the DP chapter * Revised the greedy chapter * Revised the appendix chapter * Revised the preface chapter doubly * Revised the figures
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@@ -25,9 +25,9 @@ public class binary_search {
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return -1;
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}
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/* 二分查找(左闭右开) */
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/* 二分查找(左闭右开区间) */
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static int binarySearchLCRO(int[] nums, int target) {
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// 初始化左闭右开 [0, n) ,即 i, j 分别指向数组首元素、尾元素+1
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// 初始化左闭右开区间 [0, n) ,即 i, j 分别指向数组首元素、尾元素+1
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int i = 0, j = nums.length;
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// 循环,当搜索区间为空时跳出(当 i = j 时为空)
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while (i < j) {
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@@ -51,7 +51,7 @@ public class binary_search {
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int index = binarySearch(nums, target);
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System.out.println("目标元素 6 的索引 = " + index);
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/* 二分查找(左闭右开) */
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/* 二分查找(左闭右开区间) */
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index = binarySearchLCRO(nums, target);
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System.out.println("目标元素 6 的索引 = " + index);
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}
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@@ -12,7 +12,7 @@ public class two_sum {
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/* 方法一:暴力枚举 */
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static int[] twoSumBruteForce(int[] nums, int target) {
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int size = nums.length;
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// 两层循环,时间复杂度 O(n^2)
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// 两层循环,时间复杂度为 O(n^2)
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for (int i = 0; i < size - 1; i++) {
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for (int j = i + 1; j < size; j++) {
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if (nums[i] + nums[j] == target)
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@@ -25,9 +25,9 @@ public class two_sum {
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/* 方法二:辅助哈希表 */
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static int[] twoSumHashTable(int[] nums, int target) {
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int size = nums.length;
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// 辅助哈希表,空间复杂度 O(n)
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// 辅助哈希表,空间复杂度为 O(n)
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Map<Integer, Integer> dic = new HashMap<>();
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// 单层循环,时间复杂度 O(n)
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// 单层循环,时间复杂度为 O(n)
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for (int i = 0; i < size; i++) {
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if (dic.containsKey(target - nums[i])) {
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return new int[] { dic.get(target - nums[i]), i };
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