/** * File: time_complexity.js * Created Time: 2023-01-02 * Author: RiverTwilight (contact@rene.wang) */ /* Constant complexity */ function constant(n) { let count = 0; const size = 100000; for (let i = 0; i < size; i++) count++; return count; } /* Linear complexity */ function linear(n) { let count = 0; for (let i = 0; i < n; i++) count++; return count; } /* Linear complexity (array traversal) */ function arrayTraversal(nums) { let count = 0; // The number of iterations is proportional to the array length for (let i = 0; i < nums.length; i++) { count++; } return count; } /* Quadratic complexity */ function quadratic(n) { let count = 0; // The number of iterations is proportional to the square of the input size n for (let i = 0; i < n; i++) { for (let j = 0; j < n; j++) { count++; } } return count; } /* Quadratic complexity (bubble sort) */ function bubbleSort(nums) { let count = 0; // Counter // Outer loop: the unsorted range is [0, i] for (let i = nums.length - 1; i > 0; i--) { // Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps for (let j = 0; j < i; j++) { if (nums[j] > nums[j + 1]) { // Swap nums[j] and nums[j + 1] let tmp = nums[j]; nums[j] = nums[j + 1]; nums[j + 1] = tmp; count += 3; // Swapping two elements takes 3 elementary operations } } } return count; } /* Exponential complexity (iterative implementation) */ function exponential(n) { let count = 0, base = 1; // Each cell divides into two per round, giving the sequence 1, 2, 4, 8, ..., 2^(n-1) for (let i = 0; i < n; i++) { for (let j = 0; j < base; j++) { count++; } base *= 2; } // count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1 return count; } /* Exponential complexity (recursive implementation) */ function expRecur(n) { if (n === 1) return 1; return expRecur(n - 1) + expRecur(n - 1) + 1; } /* Logarithmic complexity (iterative implementation) */ function logarithmic(n) { let count = 0; while (n > 1) { n = n / 2; count++; } return count; } /* Logarithmic complexity (recursive implementation) */ function logRecur(n) { if (n <= 1) return 0; return logRecur(n / 2) + 1; } /* Linearithmic complexity */ function linearLogRecur(n) { if (n <= 1) return 1; let count = linearLogRecur(n / 2) + linearLogRecur(n / 2); for (let i = 0; i < n; i++) { count++; } return count; } /* Factorial complexity (recursive implementation) */ function factorialRecur(n) { if (n === 0) return 1; let count = 0; // Split one problem into n subproblems for (let i = 0; i < n; i++) { count += factorialRecur(n - 1); } return count; } /* Driver code */ // Try different values of n to see how the operation count grows for each complexity const n = 8; console.log('Input size n = ' + n); let count = constant(n); console.log('Operation count for constant complexity = ' + count); count = linear(n); console.log('Operation count for linear complexity = ' + count); count = arrayTraversal(new Array(n)); console.log('Operation count for linear complexity (array traversal) = ' + count); count = quadratic(n); console.log('Operation count for quadratic complexity = ' + count); let nums = new Array(n); for (let i = 0; i < n; i++) nums[i] = n - i; // [n,n-1,...,2,1] count = bubbleSort(nums); console.log('Operation count for quadratic complexity (bubble sort) = ' + count); count = exponential(n); console.log('Operation count for exponential complexity (iterative implementation) = ' + count); count = expRecur(n); console.log('Operation count for exponential complexity (recursive implementation) = ' + count); count = logarithmic(n); console.log('Operation count for logarithmic complexity (iterative implementation) = ' + count); count = logRecur(n); console.log('Operation count for logarithmic complexity (recursive implementation) = ' + count); count = linearLogRecur(n); console.log('Operation count for linearithmic complexity (recursive implementation) = ' + count); count = factorialRecur(n); console.log('Operation count for factorial complexity (recursive implementation) = ' + count);