""" File: time_complexity.py Created Time: 2022-11-25 Author: krahets (krahets@163.com) """ def constant(n: int) -> int: """Constant complexity""" count = 0 size = 100000 for _ in range(size): count += 1 return count def linear(n: int) -> int: """Linear complexity""" count = 0 for _ in range(n): count += 1 return count def array_traversal(nums: list[int]) -> int: """Linear complexity (array traversal)""" count = 0 # The number of iterations is proportional to the array length for num in nums: count += 1 return count def quadratic(n: int) -> int: """Quadratic complexity""" count = 0 # The number of iterations is proportional to the square of the input size n for i in range(n): for j in range(n): count += 1 return count def bubble_sort(nums: list[int]) -> int: """Quadratic complexity (bubble sort)""" count = 0 # Counter # Outer loop: the unsorted range is [0, i] for i in range(len(nums) - 1, 0, -1): # Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps for j in range(i): if nums[j] > nums[j + 1]: # Swap nums[j] and nums[j + 1] tmp: int = nums[j] nums[j] = nums[j + 1] nums[j + 1] = tmp count += 3 # Swapping two elements takes 3 elementary operations return count def exponential(n: int) -> int: """Exponential complexity (iterative implementation)""" count = 0 base = 1 # Each cell divides into two per round, giving the sequence 1, 2, 4, 8, ..., 2^(n-1) for _ in range(n): for _ in range(base): count += 1 base *= 2 # count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1 return count def exp_recur(n: int) -> int: """Exponential complexity (recursive implementation)""" if n == 1: return 1 return exp_recur(n - 1) + exp_recur(n - 1) + 1 def logarithmic(n: int) -> int: """Logarithmic complexity (iterative implementation)""" count = 0 while n > 1: n = n / 2 count += 1 return count def log_recur(n: int) -> int: """Logarithmic complexity (recursive implementation)""" if n <= 1: return 0 return log_recur(n / 2) + 1 def linear_log_recur(n: int) -> int: """Linearithmic complexity""" if n <= 1: return 1 # Split into two subproblems, each half the original size count = linear_log_recur(n // 2) + linear_log_recur(n // 2) # The current subproblem includes n operations for _ in range(n): count += 1 return count def factorial_recur(n: int) -> int: """Factorial complexity (recursive implementation)""" if n == 0: return 1 count = 0 # Split one problem into n subproblems for _ in range(n): count += factorial_recur(n - 1) return count """Driver code""" if __name__ == "__main__": # Try different values of n to see how the operation count grows for each complexity n = 8 print("Input size n =", n) count = constant(n) print("Operation count for constant complexity =", count) count = linear(n) print("Operation count for linear complexity =", count) count = array_traversal([0] * n) print("Operation count for linear complexity (array traversal) =", count) count = quadratic(n) print("Operation count for quadratic complexity =", count) nums = [i for i in range(n, 0, -1)] # [n, n-1, ..., 2, 1] count = bubble_sort(nums) print("Operation count for quadratic complexity (bubble sort) =", count) count = exponential(n) print("Operation count for exponential complexity (iterative implementation) =", count) count = exp_recur(n) print("Operation count for exponential complexity (recursive implementation) =", count) count = logarithmic(n) print("Operation count for logarithmic complexity (iterative implementation) =", count) count = log_recur(n) print("Operation count for logarithmic complexity (recursive implementation) =", count) count = linear_log_recur(n) print("Operation count for linearithmic complexity (recursive implementation) =", count) count = factorial_recur(n) print("Operation count for factorial complexity (recursive implementation) =", count)