Files
Yudong Jin 2778a6f9c7 Translate all code to English (#1836)
* Review the EN heading format.

* Fix pythontutor headings.

* Fix pythontutor headings.

* bug fixes

* Fix headings in **/summary.md

* Revisit the CN-to-EN translation for Python code using Claude-4.5

* Revisit the CN-to-EN translation for Java code using Claude-4.5

* Revisit the CN-to-EN translation for Cpp code using Claude-4.5.

* Fix the dictionary.

* Fix cpp code translation for the multipart strings.

* Translate Go code to English.

* Update workflows to test EN code.

* Add EN translation for C.

* Add EN translation for CSharp.

* Add EN translation for Swift.

* Trigger the CI check.

* Revert.

* Update en/hash_map.md

* Add the EN version of Dart code.

* Add the EN version of Kotlin code.

* Add missing code files.

* Add the EN version of JavaScript code.

* Add the EN version of TypeScript code.

* Fix the workflows.

* Add the EN version of Ruby code.

* Add the EN version of Rust code.

* Update the CI check for the English version  code.

* Update Python CI check.

* Fix cmakelists for en/C code.

* Fix Ruby comments
2025-12-31 07:44:52 +08:00

53 lines
1.9 KiB
Python

"""
File: subset_sum_ii.py
Created Time: 2023-06-17
Author: krahets (krahets@163.com)
"""
def backtrack(
state: list[int], target: int, choices: list[int], start: int, res: list[list[int]]
):
"""Backtracking algorithm: Subset sum II"""
# When the subset sum equals target, record the solution
if target == 0:
res.append(list(state))
return
# Traverse all choices
# Pruning 2: start traversing from start to avoid generating duplicate subsets
# Pruning 3: start traversing from start to avoid repeatedly selecting the same element
for i in range(start, len(choices)):
# Pruning 1: if the subset sum exceeds target, end the loop directly
# This is because the array is sorted, and later elements are larger, so the subset sum will definitely exceed target
if target - choices[i] < 0:
break
# Pruning 4: if this element equals the left element, it means this search branch is duplicate, skip it directly
if i > start and choices[i] == choices[i - 1]:
continue
# Attempt: make choice, update target, start
state.append(choices[i])
# Proceed to the next round of selection
backtrack(state, target - choices[i], choices, i + 1, res)
# Backtrack: undo choice, restore to previous state
state.pop()
def subset_sum_ii(nums: list[int], target: int) -> list[list[int]]:
"""Solve subset sum II"""
state = [] # State (subset)
nums.sort() # Sort nums
start = 0 # Start point for traversal
res = [] # Result list (subset list)
backtrack(state, target, nums, start, res)
return res
"""Driver Code"""
if __name__ == "__main__":
nums = [4, 4, 5]
target = 9
res = subset_sum_ii(nums, target)
print(f"Input array nums = {nums}, target = {target}")
print(f"All subsets with sum equal to {target} res = {res}")