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hello-algo/en/codes/swift/chapter_tree/binary_search_tree.swift
Yudong Jin 2778a6f9c7 Translate all code to English (#1836)
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2025-12-31 07:44:52 +08:00

174 lines
4.8 KiB
Swift

/**
* File: binary_search_tree.swift
* Created Time: 2023-01-26
* Author: nuomi1 (nuomi1@qq.com)
*/
import utils
/* Binary search tree */
class BinarySearchTree {
private var root: TreeNode?
/* Constructor */
init() {
// Initialize empty tree
root = nil
}
/* Get binary tree root node */
func getRoot() -> TreeNode? {
root
}
/* Search node */
func search(num: Int) -> TreeNode? {
var cur = root
// Loop search, exit after passing leaf node
while cur != nil {
// Target node is in cur's right subtree
if cur!.val < num {
cur = cur?.right
}
// Target node is in cur's left subtree
else if cur!.val > num {
cur = cur?.left
}
// Found target node, exit loop
else {
break
}
}
// Return target node
return cur
}
/* Insert node */
func insert(num: Int) {
// If tree is empty, initialize root node
if root == nil {
root = TreeNode(x: num)
return
}
var cur = root
var pre: TreeNode?
// Loop search, exit after passing leaf node
while cur != nil {
// Found duplicate node, return directly
if cur!.val == num {
return
}
pre = cur
// Insertion position is in cur's right subtree
if cur!.val < num {
cur = cur?.right
}
// Insertion position is in cur's left subtree
else {
cur = cur?.left
}
}
// Insert node
let node = TreeNode(x: num)
if pre!.val < num {
pre?.right = node
} else {
pre?.left = node
}
}
/* Remove node */
func remove(num: Int) {
// If tree is empty, return directly
if root == nil {
return
}
var cur = root
var pre: TreeNode?
// Loop search, exit after passing leaf node
while cur != nil {
// Found node to delete, exit loop
if cur!.val == num {
break
}
pre = cur
// Node to delete is in cur's right subtree
if cur!.val < num {
cur = cur?.right
}
// Node to delete is in cur's left subtree
else {
cur = cur?.left
}
}
// If no node to delete, return directly
if cur == nil {
return
}
// Number of child nodes = 0 or 1
if cur?.left == nil || cur?.right == nil {
// When number of child nodes = 0 / 1, child = null / that child node
let child = cur?.left ?? cur?.right
// Delete node cur
if cur !== root {
if pre?.left === cur {
pre?.left = child
} else {
pre?.right = child
}
} else {
// If deleted node is root node, reassign root node
root = child
}
}
// Number of child nodes = 2
else {
// Get next node of cur in inorder traversal
var tmp = cur?.right
while tmp?.left != nil {
tmp = tmp?.left
}
// Recursively delete node tmp
remove(num: tmp!.val)
// Replace cur with tmp
cur?.val = tmp!.val
}
}
}
@main
enum _BinarySearchTree {
/* Driver Code */
static func main() {
/* Initialize binary search tree */
let bst = BinarySearchTree()
// Please note that different insertion orders will generate different binary trees, this sequence can generate a perfect binary tree
let nums = [8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15]
for num in nums {
bst.insert(num: num)
}
print("\nInitialized binary tree is\n")
PrintUtil.printTree(root: bst.getRoot())
/* Search node */
let node = bst.search(num: 7)
print("\nFound node object is \(node!), node value = \(node!.val)")
/* Insert node */
bst.insert(num: 16)
print("\nAfter inserting node 16, binary tree is\n")
PrintUtil.printTree(root: bst.getRoot())
/* Remove node */
bst.remove(num: 1)
print("\nAfter removing node 1, binary tree is\n")
PrintUtil.printTree(root: bst.getRoot())
bst.remove(num: 2)
print("\nAfter removing node 2, binary tree is\n")
PrintUtil.printTree(root: bst.getRoot())
bst.remove(num: 4)
print("\nAfter removing node 4, binary tree is\n")
PrintUtil.printTree(root: bst.getRoot())
}
}