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hello-algo/en/codes/javascript/chapter_searching/binary_search_insertion.js
Yudong Jin 14c314c08c Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese

* Polish three English explanations after reader-focused review
2026-10-31 03:35:51 +08:00

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2.2 KiB
JavaScript

/**
* File: binary_search_insertion.js
* Created Time: 2023-08-22
* Author: Gaofer Chou (gaofer-chou@qq.com)
*/
/* Find an insertion point using binary search (no duplicates) */
function binarySearchInsertionSimple(nums, target) {
let i = 0,
j = nums.length - 1; // Initialize the closed interval [0, n-1]
while (i <= j) {
const m = Math.floor(i + (j - i) / 2); // Calculate midpoint index m, using Math.floor() to round down
if (nums[m] < target) {
i = m + 1; // Target must be in [m+1, j] if it exists
} else if (nums[m] > target) {
j = m - 1; // Target must be in [i, m-1] if it exists
} else {
return m; // Target was found; return insertion point m
}
}
// Target was not found; return insertion point i
return i;
}
/* Find an insertion point using binary search (with duplicates) */
function binarySearchInsertion(nums, target) {
let i = 0,
j = nums.length - 1; // Initialize the closed interval [0, n-1]
while (i <= j) {
const m = Math.floor(i + (j - i) / 2); // Calculate midpoint index m, using Math.floor() to round down
if (nums[m] < target) {
i = m + 1; // Target must be in [m+1, j] if it exists
} else if (nums[m] > target) {
j = m - 1; // Target must be in [i, m-1] if it exists
} else {
j = m - 1; // Continue in [i, m-1] to find the rightmost element smaller than target
}
}
// Return insertion point i
return i;
}
/* Driver code */
// Array with no duplicate elements
let nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35];
console.log('\nArray nums = ' + nums);
// Find an insertion point using binary search
for (const target of [6, 9]) {
const index = binarySearchInsertionSimple(nums, target);
console.log('Element ' + target + ' has insertion index ' + index);
}
// Array containing duplicate elements
nums = [1, 3, 6, 6, 6, 6, 6, 10, 12, 15];
console.log('\nArray nums = ' + nums);
// Find an insertion point using binary search
for (const target of [2, 6, 20]) {
const index = binarySearchInsertion(nums, target);
console.log('Element ' + target + ' has insertion index ' + index);
}
module.exports = {
binarySearchInsertion,
};