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* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
140 lines
4.4 KiB
JavaScript
140 lines
4.4 KiB
JavaScript
/**
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* File: binary_search_tree.js
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* Created Time: 2022-12-04
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* Author: IsChristina (christinaxia77@foxmail.com)
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*/
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const { TreeNode } = require('../modules/TreeNode');
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const { printTree } = require('../modules/PrintUtil');
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/* Binary search tree */
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class BinarySearchTree {
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/* Constructor */
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constructor() {
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// Initialize an empty tree
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this.root = null;
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}
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/* Get the root of the binary tree */
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getRoot() {
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return this.root;
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}
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/* Find a node */
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search(num) {
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let cur = this.root;
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// Search in a loop until reaching a null reference beyond a leaf
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while (cur !== null) {
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// The target node lies in the right subtree of cur
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if (cur.val < num) cur = cur.right;
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// The target node lies in the left subtree of cur
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else if (cur.val > num) cur = cur.left;
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// The target node was found; exit the loop
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else break;
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}
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// Return the target node
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return cur;
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}
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/* Insert a node */
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insert(num) {
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// If the tree is empty, initialize the root node
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if (this.root === null) {
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this.root = new TreeNode(num);
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return;
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}
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let cur = this.root,
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pre = null;
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// Search in a loop until reaching a null reference beyond a leaf
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while (cur !== null) {
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// Return immediately if a duplicate node is found
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if (cur.val === num) return;
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pre = cur;
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// The insertion position lies in the right subtree of cur
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if (cur.val < num) cur = cur.right;
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// The insertion position lies in the left subtree of cur
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else cur = cur.left;
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}
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// Insert a node
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const node = new TreeNode(num);
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if (pre.val < num) pre.right = node;
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else pre.left = node;
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}
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/* Remove a node */
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remove(num) {
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// Return immediately if the tree is empty
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if (this.root === null) return;
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let cur = this.root,
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pre = null;
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// Search in a loop until reaching a null reference beyond a leaf
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while (cur !== null) {
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// The node to remove was found; exit the loop
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if (cur.val === num) break;
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pre = cur;
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// The node to remove lies in the right subtree of cur
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if (cur.val < num) cur = cur.right;
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// The node to remove lies in the left subtree of cur
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else cur = cur.left;
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}
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// Return immediately if the node to remove does not exist
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if (cur === null) return;
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// Number of children = 0 or 1
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if (cur.left === null || cur.right === null) {
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// With 0 / 1 children, child is null / the child node, respectively
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const child = cur.left !== null ? cur.left : cur.right;
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// Remove node cur
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if (cur !== this.root) {
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if (pre.left === cur) pre.left = child;
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else pre.right = child;
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} else {
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// If the removed node is the root, assign the new root
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this.root = child;
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}
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}
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// Number of children = 2
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else {
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// Get the inorder successor of cur
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let tmp = cur.right;
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while (tmp.left !== null) {
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tmp = tmp.left;
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}
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// Recursively remove node tmp
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this.remove(tmp.val);
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// Replace the value of cur with the value of tmp
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cur.val = tmp.val;
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}
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}
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}
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/* Driver code */
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/* Initialize the binary search tree */
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const bst = new BinarySearchTree();
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// Different insertion orders produce different binary trees; this sequence produces a perfect binary tree
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const nums = [8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15];
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for (const num of nums) {
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bst.insert(num);
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}
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console.log('\nThe initialized binary tree is:\n');
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printTree(bst.getRoot());
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/* Find a node */
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const node = bst.search(7);
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console.log('\nFound node object: ' + node + ', node value = ' + node.val);
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/* Insert a node */
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bst.insert(16);
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console.log('\nBinary tree after inserting node 16:\n');
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printTree(bst.getRoot());
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/* Remove a node */
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bst.remove(1);
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console.log('\nBinary tree after removing node 1:\n');
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printTree(bst.getRoot());
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bst.remove(2);
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console.log('\nBinary tree after removing node 2:\n');
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printTree(bst.getRoot());
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bst.remove(4);
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console.log('\nBinary tree after removing node 4:\n');
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printTree(bst.getRoot());
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