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제 10 장 &nbsp; 탐색
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10.1 &nbsp; 이진 탐색
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10.2 &nbsp; 이진 탐색으로 삽입 위치 찾기
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10.3 &nbsp; 이진 탐색으로 경계 찾기
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10.4 &nbsp; 해시를 이용한 최적화 전략
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10.5 &nbsp; 탐색 알고리즘 다시 보기
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제 11 장 &nbsp; 정렬
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11.2 &nbsp; 선택 정렬
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11.3 &nbsp; 버블 정렬
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11.4 &nbsp; 삽입 정렬
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11.5 &nbsp; 퀵 정렬
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11.6 &nbsp; 병합 정렬
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11.8 &nbsp; 버킷 정렬
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11.9 &nbsp; 계수 정렬
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11.10 &nbsp; 기수 정렬
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11.11 &nbsp; 요약
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제 12 장 &nbsp; 분할 정복
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12.1 &nbsp; 분할 정복 알고리즘
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12.2 &nbsp; 분할 정복 탐색 전략
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12.3 &nbsp; 이진 트리 구성 문제
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12.4 &nbsp; 하노이의 탑 문제
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12.5 &nbsp; 요약
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제 13 장 &nbsp; 백트래킹
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13.4 &nbsp; n-퀸 문제
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14.2 &nbsp; 동적 계획법 문제의 특성
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<h1 id="36">3.6 &nbsp; 연습 문제<a class="headerlink" href="#36" title="고유 링크">&para;</a></h1>
<h2 id="361">3.6.1 &nbsp; 개념 확인<a class="headerlink" href="#361" title="고유 링크">&para;</a></h2>
<h3 id="1">1. &nbsp; 일상 속 데이터의 관계<a class="headerlink" href="#1" title="고유 링크">&para;</a></h3>
<p>데이터 사이의 관계를 바탕으로 다음 세 상황에 대해 ‘선형 구조, 트리 구조, 네트워크 구조’ 중 하나를 고르고 이유를 설명하라.</p>
<!-- numbered-subquestions -->
<ol>
<li>학생들이 한 줄로 서 있고, 각자 바로 앞과 뒤에 있는 사람만 신경 쓴다.</li>
<li>학교를 ‘학교 → 학년 → 학급’의 계층으로 나누어 관리한다.</li>
<li>도시의 도로가 여러 교차로를 연결한다. 한 교차로에서 여러 다른 교차로로 갈 수 있으며 순환하는 경로도 생길 수 있다.</li>
</ol>
<details class="success">
<summary>참고 답안</summary>
<ol>
<li>
<p>선형 구조다. 맨 앞과 맨 뒤에 선 사람을 제외하면 각 사람은 앞뒤로 한 사람씩만 이웃하며, 관계가 하나의 선을 따라 이어진다.</p>
</li>
<li>
<p>트리 구조다. 각 학급은 한 학년에 속하고 각 학년은 학교에 속하므로, 관계가 위에서 아래로 계층적으로 펼쳐진다.</p>
</li>
<li>
<p>네트워크 구조다. 한 교차로가 여러 교차로와 연결될 수 있고 경로들이 순환을 이룰 수도 있으므로, 하나의 순서나 엄격한 계층으로 나열할 수 없다.</p>
<p>구조를 판단할 때는 메모리에서 차지하는 공간보다 원소 사이의 관계를 먼저 살펴보아야 한다.</p>
</li>
</ol>
</details>
<h3 id="2">2. &nbsp; 논리적 순서를 메모리에 저장하는 방법<a class="headerlink" href="#2" title="고유 링크">&para;</a></h3>
<p>논리적 순서 <code>A → B → C</code>를 저장하기 위해 다음과 같이 단순화한 두 메모리 배치 방식을 생각해 보자.</p>
<ul>
<li>방법 가: <code>A, B, C</code>를 각각 번호가 <code>20, 21, 22</code>인 메모리 칸에 저장한다.</li>
<li>방법 나: <code>A, B, C</code>를 각각 번호가 <code>20, 7, 31</code>인 메모리 칸에 저장하고, <code>A</code>에 <code>B</code>의 위치를, <code>B</code>에 <code>C</code>의 위치를 기록한다.</li>
</ul>
<!-- numbered-subquestions -->
<ol>
<li>어느 방법이 연속 공간 저장이고, 어느 방법이 분산 공간 저장인가?</li>
<li>두 방법은 각각 배열과 연결 리스트 중 어느 쪽에 더 가까운가?</li>
<li>방법 나는 메모리 칸의 번호가 크기순으로 정렬되어 있지 않은데, 어떻게 <code>A → B → C</code>의 논리적 순서를 나타낼 수 있는가?</li>
</ol>
<details class="success">
<summary>참고 답안</summary>
<ol>
<li>
<p>방법 가는 연속된 메모리 칸을 사용하므로 연속 공간 저장이다. 방법 나는 노드가 여러 위치에 흩어져 있으므로 분산 공간 저장이다.</p>
</li>
<li>
<p>방법 가는 배열에, 방법 나는 연결 리스트에 더 가깝다.</p>
</li>
<li>
<p>논리적 순서는 메모리 칸 번호의 크기가 아니라 노드 사이에 기록된 연결 관계로 결정된다.
<code>A</code>에 기록된 위치에서 <code>B</code>를 찾고, 다시 <code>B</code>에 기록된 위치에서 <code>C</code>를 찾을 수 있으므로 <code>A, B, C</code>에 차례대로 접근할 수 있다.</p>
<p>이는 논리적 구조와 물리적 구조가 같은 데이터 집합을 바라보는 서로 다른 두 관점임을 보여 준다.</p>
</li>
</ol>
</details>
<h3 id="3">3. &nbsp; 과제 기록의 자료형과 구조<a class="headerlink" href="#3" title="고유 링크">&para;</a></h3>
<p>한 학습 모임에서 학생 4명의 과제 제출 여부를 좌석 순서대로 기록한 결과가 다음과 같다.</p>
<p><code>[true, false, true, true]</code></p>
<!-- numbered-subquestions -->
<ol>
<li>각 원소에는 어떤 기본 자료형이 적합한가?</li>
<li>이 4개 원소를 좌석 순서대로 한 줄에 나열한 것은 어떤 논리적 구조인가?</li>
<li>나중에 각 학생의 과제 점수 <code>[90, 0, 85, 100]</code>를 기록하도록 바꾼다면, 달라지는 것은 데이터의 ‘내용 유형’인가, ‘조직 방식’인가? 이유를 설명하라.</li>
</ol>
<details class="success">
<summary>참고 답안</summary>
<ol>
<li>
<p>각 원소는 ‘예’ 또는 ‘아니요’만 나타내므로 불리언 자료형 <code>bool</code>이 적합하다.</p>
</li>
<li>
<p>원소들이 좌석 순서대로 나열되어 선형 구조를 이루며, 배열에 저장할 수 있다.</p>
</li>
<li>
<p>달라지는 것은 내용 유형이다. 원소가 불리언 값에서 정수로 바뀐다. 조직 방식은 바뀌지 않는다.
데이터는 여전히 좌석 순서대로 한 줄에 나열되어 있으므로 배열이라는 선형 구조를 사용할 수 있다.</p>
<p>기본 자료형은 ‘무엇을 저장하는가’를, 자료 구조는 ‘데이터를 어떻게 구성하는가’를 설명한다.</p>
</li>
</ol>
</details>
<h2 id="362">3.6.2 &nbsp; 프로그래밍 연습<a class="headerlink" href="#362" title="고유 링크">&para;</a></h2>
<h3 id="1-1">1. &nbsp; 이진수 표현에서 1의 개수 세기<a class="headerlink" href="#1-1" title="고유 링크">&para;</a></h3>
<p>음이 아닌 정수 <code>n</code>이 주어질 때, 이진수 표현에 포함된 1의 개수를 구하라.</p>
<p>비트 연산을 사용해야 하며, 이진수 표현을 문자열로 변환하거나 1의 개수를 바로 세어 주는 내장 함수를 사용해서는 안 된다.</p>
<details class="tip">
<summary>풀이 힌트</summary>
<ol>
<li>n &amp; 1로 n의 가장 오른쪽 비트를 얻어 그 비트가 1인지 확인할 수 있다.</li>
<li>오른쪽으로 한 비트 이동하면 현재 가장 오른쪽 비트가 제거된다. 대부분의 언어에서는 &gt;&gt; 연산자를 사용한다.</li>
<li>비트를 하나씩 확인하고 오른쪽으로 이동하는 방법을 완성한 뒤, n &amp; (n - 1)이 n의 가장 오른쪽 1을 0으로 바꾼다는 점도 살펴보자.</li>
</ol>
</details>
<p><a class="rounded-button exercise-button" href="https://leetcode.com/problems/number-of-1-bits/" rel="noopener noreferrer" target="_blank">LeetCode</a></p>
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