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hello-algo/en/codes/cpp/chapter_computational_complexity/time_complexity.cpp
Yudong Jin 14c314c08c Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese

* Polish three English explanations after reader-focused review
2026-10-31 03:35:51 +08:00

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C++

/**
* File: time_complexity.cpp
* Created Time: 2022-11-25
* Author: krahets (krahets@163.com)
*/
#include "../utils/common.hpp"
/* Constant complexity */
int constant(int n) {
int count = 0;
int size = 100000;
for (int i = 0; i < size; i++)
count++;
return count;
}
/* Linear complexity */
int linear(int n) {
int count = 0;
for (int i = 0; i < n; i++)
count++;
return count;
}
/* Linear complexity (array traversal) */
int arrayTraversal(vector<int> &nums) {
int count = 0;
// The number of iterations is proportional to the array length
for (int num : nums) {
count++;
}
return count;
}
/* Quadratic complexity */
int quadratic(int n) {
int count = 0;
// The number of iterations is proportional to the square of the input size n
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
count++;
}
}
return count;
}
/* Quadratic complexity (bubble sort) */
int bubbleSort(vector<int> &nums) {
int count = 0; // Counter
// Outer loop: the unsorted range is [0, i]
for (int i = nums.size() - 1; i > 0; i--) {
// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
for (int j = 0; j < i; j++) {
if (nums[j] > nums[j + 1]) {
// Swap nums[j] and nums[j + 1]
int tmp = nums[j];
nums[j] = nums[j + 1];
nums[j + 1] = tmp;
count += 3; // Swapping two elements takes 3 elementary operations
}
}
}
return count;
}
/* Exponential complexity (iterative implementation) */
int exponential(int n) {
int count = 0, base = 1;
// Each cell divides into two per round, giving the sequence 1, 2, 4, 8, ..., 2^(n-1)
for (int i = 0; i < n; i++) {
for (int j = 0; j < base; j++) {
count++;
}
base *= 2;
}
// count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
return count;
}
/* Exponential complexity (recursive implementation) */
int expRecur(int n) {
if (n == 1)
return 1;
return expRecur(n - 1) + expRecur(n - 1) + 1;
}
/* Logarithmic complexity (iterative implementation) */
int logarithmic(int n) {
int count = 0;
while (n > 1) {
n = n / 2;
count++;
}
return count;
}
/* Logarithmic complexity (recursive implementation) */
int logRecur(int n) {
if (n <= 1)
return 0;
return logRecur(n / 2) + 1;
}
/* Linearithmic complexity */
int linearLogRecur(int n) {
if (n <= 1)
return 1;
int count = linearLogRecur(n / 2) + linearLogRecur(n / 2);
for (int i = 0; i < n; i++) {
count++;
}
return count;
}
/* Factorial complexity (recursive implementation) */
int factorialRecur(int n) {
if (n == 0)
return 1;
int count = 0;
// Split one problem into n subproblems
for (int i = 0; i < n; i++) {
count += factorialRecur(n - 1);
}
return count;
}
/* Driver code */
int main() {
// Try different values of n to see how the operation count grows for each complexity
int n = 8;
cout << "Input size n = " << n << endl;
int count = constant(n);
cout << "Operation count for constant complexity = " << count << endl;
count = linear(n);
cout << "Operation count for linear complexity = " << count << endl;
vector<int> arr(n);
count = arrayTraversal(arr);
cout << "Operation count for linear complexity (array traversal) = " << count << endl;
count = quadratic(n);
cout << "Operation count for quadratic complexity = " << count << endl;
vector<int> nums(n);
for (int i = 0; i < n; i++)
nums[i] = n - i; // [n,n-1,...,2,1]
count = bubbleSort(nums);
cout << "Operation count for quadratic complexity (bubble sort) = " << count << endl;
count = exponential(n);
cout << "Operation count for exponential complexity (iterative implementation) = " << count << endl;
count = expRecur(n);
cout << "Operation count for exponential complexity (recursive implementation) = " << count << endl;
count = logarithmic(n);
cout << "Operation count for logarithmic complexity (iterative implementation) = " << count << endl;
count = logRecur(n);
cout << "Operation count for logarithmic complexity (recursive implementation) = " << count << endl;
count = linearLogRecur(n);
cout << "Operation count for linearithmic complexity (recursive implementation) = " << count << endl;
count = factorialRecur(n);
cout << "Operation count for factorial complexity (recursive implementation) = " << count << endl;
return 0;
}