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* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
169 lines
4.6 KiB
C++
169 lines
4.6 KiB
C++
/**
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* File: time_complexity.cpp
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* Created Time: 2022-11-25
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* Author: krahets (krahets@163.com)
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*/
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#include "../utils/common.hpp"
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/* Constant complexity */
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int constant(int n) {
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int count = 0;
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int size = 100000;
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for (int i = 0; i < size; i++)
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count++;
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return count;
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}
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/* Linear complexity */
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int linear(int n) {
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int count = 0;
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for (int i = 0; i < n; i++)
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count++;
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return count;
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}
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/* Linear complexity (array traversal) */
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int arrayTraversal(vector<int> &nums) {
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int count = 0;
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// The number of iterations is proportional to the array length
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for (int num : nums) {
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count++;
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}
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return count;
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}
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/* Quadratic complexity */
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int quadratic(int n) {
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int count = 0;
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// The number of iterations is proportional to the square of the input size n
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for (int i = 0; i < n; i++) {
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for (int j = 0; j < n; j++) {
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count++;
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}
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}
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return count;
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}
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/* Quadratic complexity (bubble sort) */
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int bubbleSort(vector<int> &nums) {
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int count = 0; // Counter
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// Outer loop: the unsorted range is [0, i]
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for (int i = nums.size() - 1; i > 0; i--) {
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// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
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for (int j = 0; j < i; j++) {
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if (nums[j] > nums[j + 1]) {
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// Swap nums[j] and nums[j + 1]
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int tmp = nums[j];
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nums[j] = nums[j + 1];
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nums[j + 1] = tmp;
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count += 3; // Swapping two elements takes 3 elementary operations
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}
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}
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}
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return count;
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}
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/* Exponential complexity (iterative implementation) */
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int exponential(int n) {
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int count = 0, base = 1;
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// Each cell divides into two per round, giving the sequence 1, 2, 4, 8, ..., 2^(n-1)
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for (int i = 0; i < n; i++) {
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for (int j = 0; j < base; j++) {
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count++;
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}
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base *= 2;
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}
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// count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
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return count;
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}
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/* Exponential complexity (recursive implementation) */
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int expRecur(int n) {
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if (n == 1)
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return 1;
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return expRecur(n - 1) + expRecur(n - 1) + 1;
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}
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/* Logarithmic complexity (iterative implementation) */
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int logarithmic(int n) {
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int count = 0;
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while (n > 1) {
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n = n / 2;
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count++;
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}
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return count;
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}
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/* Logarithmic complexity (recursive implementation) */
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int logRecur(int n) {
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if (n <= 1)
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return 0;
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return logRecur(n / 2) + 1;
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}
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/* Linearithmic complexity */
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int linearLogRecur(int n) {
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if (n <= 1)
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return 1;
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int count = linearLogRecur(n / 2) + linearLogRecur(n / 2);
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for (int i = 0; i < n; i++) {
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count++;
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}
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return count;
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}
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/* Factorial complexity (recursive implementation) */
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int factorialRecur(int n) {
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if (n == 0)
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return 1;
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int count = 0;
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// Split one problem into n subproblems
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for (int i = 0; i < n; i++) {
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count += factorialRecur(n - 1);
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}
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return count;
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}
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/* Driver code */
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int main() {
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// Try different values of n to see how the operation count grows for each complexity
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int n = 8;
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cout << "Input size n = " << n << endl;
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int count = constant(n);
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cout << "Operation count for constant complexity = " << count << endl;
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count = linear(n);
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cout << "Operation count for linear complexity = " << count << endl;
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vector<int> arr(n);
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count = arrayTraversal(arr);
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cout << "Operation count for linear complexity (array traversal) = " << count << endl;
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count = quadratic(n);
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cout << "Operation count for quadratic complexity = " << count << endl;
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vector<int> nums(n);
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for (int i = 0; i < n; i++)
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nums[i] = n - i; // [n,n-1,...,2,1]
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count = bubbleSort(nums);
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cout << "Operation count for quadratic complexity (bubble sort) = " << count << endl;
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count = exponential(n);
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cout << "Operation count for exponential complexity (iterative implementation) = " << count << endl;
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count = expRecur(n);
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cout << "Operation count for exponential complexity (recursive implementation) = " << count << endl;
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count = logarithmic(n);
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cout << "Operation count for logarithmic complexity (iterative implementation) = " << count << endl;
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count = logRecur(n);
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cout << "Operation count for logarithmic complexity (recursive implementation) = " << count << endl;
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count = linearLogRecur(n);
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cout << "Operation count for linearithmic complexity (recursive implementation) = " << count << endl;
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count = factorialRecur(n);
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cout << "Operation count for factorial complexity (recursive implementation) = " << count << endl;
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return 0;
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}
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