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* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
51 lines
1.9 KiB
C#
51 lines
1.9 KiB
C#
/**
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* File: binary_search_edge.cs
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* Created Time: 2023-08-06
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_searching;
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public class binary_search_edge {
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/* Find the leftmost occurrence of target using binary search */
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int BinarySearchLeftEdge(int[] nums, int target) {
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// This is equivalent to finding the insertion point of target
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int i = binary_search_insertion.BinarySearchInsertion(nums, target);
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// If target was not found, return -1
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if (i == nums.Length || nums[i] != target) {
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return -1;
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}
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// Target was found; return index i
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return i;
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}
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/* Find the rightmost occurrence of target using binary search */
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int BinarySearchRightEdge(int[] nums, int target) {
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// Reduce the problem to finding the leftmost insertion point of target + 1
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int i = binary_search_insertion.BinarySearchInsertion(nums, target + 1);
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// j is the candidate index of the rightmost target; i is the insertion point after all elements <= target
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int j = i - 1;
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// If target was not found, return -1
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if (j == -1 || nums[j] != target) {
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return -1;
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}
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// Target was found; return index j
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return j;
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}
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[Test]
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public void Test() {
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// Array containing duplicate elements
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int[] nums = [1, 3, 6, 6, 6, 6, 6, 10, 12, 15];
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Console.WriteLine("\nArray nums = " + nums.PrintList());
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// Find the left and right boundaries using binary search
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foreach (int target in new int[] { 6, 7 }) {
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int index = BinarySearchLeftEdge(nums, target);
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Console.WriteLine("Leftmost occurrence of " + target + " has index " + index);
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index = BinarySearchRightEdge(nums, target);
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Console.WriteLine("Rightmost occurrence of " + target + " has index " + index);
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}
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}
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}
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