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hello-algo/en/codes/java/chapter_backtracking/n_queens.java
Yudong Jin 14c314c08c Retranslate the complete English edition from Simplified Chinese (#2010)
* Retranslate the complete English edition from Simplified Chinese

* Polish three English explanations after reader-focused review
2026-10-31 03:35:51 +08:00

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2.9 KiB
Java

/**
* File: n_queens.java
* Created Time: 2023-05-04
* Author: krahets (krahets@163.com)
*/
package chapter_backtracking;
import java.util.*;
public class n_queens {
/* Backtracking: n-queens */
public static void backtrack(int row, int n, List<List<String>> state, List<List<List<String>>> res,
boolean[] cols, boolean[] diags1, boolean[] diags2) {
// Record a solution when a queen has been placed in every row
if (row == n) {
List<List<String>> copyState = new ArrayList<>();
for (List<String> sRow : state) {
copyState.add(new ArrayList<>(sRow));
}
res.add(copyState);
return;
}
// Iterate over all columns
for (int col = 0; col < n; col++) {
// Calculate the main-diagonal and anti-diagonal indices for this square
int diag1 = row - col + n - 1;
int diag2 = row + col;
// Prune: the square must have no queen in its column, main diagonal, or anti-diagonal
if (!cols[col] && !diags1[diag1] && !diags2[diag2]) {
// Try: place a queen on this square
state.get(row).set(col, "Q");
cols[col] = diags1[diag1] = diags2[diag2] = true;
// Place a queen in the next row
backtrack(row + 1, n, state, res, cols, diags1, diags2);
// Backtrack: restore this square to empty
state.get(row).set(col, "#");
cols[col] = diags1[diag1] = diags2[diag2] = false;
}
}
}
/* Solve the n-queens problem */
public static List<List<List<String>>> nQueens(int n) {
// Initialize an n*n board, where 'Q' represents a queen and '#' represents an empty square
List<List<String>> state = new ArrayList<>();
for (int i = 0; i < n; i++) {
List<String> row = new ArrayList<>();
for (int j = 0; j < n; j++) {
row.add("#");
}
state.add(row);
}
boolean[] cols = new boolean[n]; // Track whether a column contains a queen
boolean[] diags1 = new boolean[2 * n - 1]; // Track whether a main diagonal contains a queen
boolean[] diags2 = new boolean[2 * n - 1]; // Track whether an anti-diagonal contains a queen
List<List<List<String>>> res = new ArrayList<>();
backtrack(0, n, state, res, cols, diags1, diags2);
return res;
}
public static void main(String[] args) {
int n = 4;
List<List<List<String>>> res = nQueens(n);
System.out.println("Input board side length: " + n);
System.out.println("There are " + res.size() + " queen placements");
for (List<List<String>> state : res) {
System.out.println("--------------------");
for (List<String> row : state) {
System.out.println(row);
}
}
}
}