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* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
66 lines
1.8 KiB
Ruby
66 lines
1.8 KiB
Ruby
=begin
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File: coin_change.rb
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Created Time: 2024-05-29
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Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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=end
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### Coin change: dynamic programming ###
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def coin_change_dp(coins, amt)
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n = coins.length
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_MAX = amt + 1
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# Initialize the dp table
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dp = Array.new(n + 1) { Array.new(amt + 1, 0) }
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# State transitions: first row and first column
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(1...(amt + 1)).each { |a| dp[0][a] = _MAX }
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# State transitions: remaining rows and columns
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for i in 1...(n + 1)
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for a in 1...(amt + 1)
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if coins[i - 1] > a
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# If the coin exceeds the current amount a, do not choose coin i
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dp[i][a] = dp[i - 1][a]
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else
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# Take the smaller result of not choosing and choosing coin i
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dp[i][a] = [dp[i - 1][a], dp[i][a - coins[i - 1]] + 1].min
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end
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end
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end
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dp[n][amt] != _MAX ? dp[n][amt] : -1
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end
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### Coin change: space-optimized dynamic programming ###
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def coin_change_dp_comp(coins, amt)
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n = coins.length
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_MAX = amt + 1
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# Initialize the dp table
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dp = Array.new(amt + 1, _MAX)
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dp[0] = 0
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# State transitions
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for i in 1...(n + 1)
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# Traverse in increasing order
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for a in 1...(amt + 1)
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if coins[i - 1] > a
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# If the coin exceeds the current amount a, do not choose coin i
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dp[a] = dp[a]
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else
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# Take the smaller result of not choosing and choosing coin i
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dp[a] = [dp[a], dp[a - coins[i - 1]] + 1].min
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end
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end
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end
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dp[amt] != _MAX ? dp[amt] : -1
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end
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### Driver code ###
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if __FILE__ == $0
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coins = [1, 2, 5]
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amt = 4
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# Dynamic programming
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res = coin_change_dp(coins, amt)
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puts "Minimum number of coins needed to make the target amount: #{res}"
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# Space-optimized dynamic programming
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res = coin_change_dp_comp(coins, amt)
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puts "Minimum number of coins needed to make the target amount: #{res}"
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end
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