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* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
142 lines
3.7 KiB
Swift
142 lines
3.7 KiB
Swift
/**
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* File: array_binary_tree.swift
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* Created Time: 2023-07-23
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* Author: nuomi1 (nuomi1@qq.com)
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*/
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import utils
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/* Binary tree class using an array representation */
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class ArrayBinaryTree {
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private var tree: [Int?]
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/* Constructor */
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init(arr: [Int?]) {
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tree = arr
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}
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/* Length of the backing array */
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func size() -> Int {
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tree.count
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}
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/* Get the value of the node at index i */
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func val(i: Int) -> Int? {
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// If the index is out of bounds, return nil to represent an empty position
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if i < 0 || i >= size() {
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return nil
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}
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return tree[i]
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}
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/* Get the left child index of the node at index i */
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func left(i: Int) -> Int {
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2 * i + 1
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}
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/* Get the right child index of the node at index i */
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func right(i: Int) -> Int {
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2 * i + 2
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}
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/* Get the parent index of the node at index i */
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func parent(i: Int) -> Int {
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(i - 1) / 2
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}
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/* Level-order traversal */
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func levelOrder() -> [Int] {
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var res: [Int] = []
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// Traverse the array directly
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for i in 0 ..< size() {
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if let val = val(i: i) {
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res.append(val)
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}
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}
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return res
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}
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/* Depth-first traversal */
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private func dfs(i: Int, order: String, res: inout [Int]) {
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// Return if this position is empty
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guard let val = val(i: i) else {
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return
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}
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// Preorder traversal
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if order == "pre" {
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res.append(val)
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}
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dfs(i: left(i: i), order: order, res: &res)
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// Inorder traversal
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if order == "in" {
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res.append(val)
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}
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dfs(i: right(i: i), order: order, res: &res)
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// Postorder traversal
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if order == "post" {
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res.append(val)
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}
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}
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/* Preorder traversal */
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func preOrder() -> [Int] {
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var res: [Int] = []
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dfs(i: 0, order: "pre", res: &res)
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return res
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}
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/* Inorder traversal */
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func inOrder() -> [Int] {
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var res: [Int] = []
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dfs(i: 0, order: "in", res: &res)
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return res
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}
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/* Postorder traversal */
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func postOrder() -> [Int] {
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var res: [Int] = []
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dfs(i: 0, order: "post", res: &res)
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return res
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}
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}
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@main
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enum _ArrayBinaryTree {
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/* Driver code */
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static func main() {
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// Initialize the binary tree
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// Use a helper function that builds a binary tree directly from an array
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let arr = [1, 2, 3, 4, nil, 6, 7, 8, 9, nil, nil, 12, nil, nil, 15]
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let root = TreeNode.listToTree(arr: arr)
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print("\nInitialize the binary tree\n")
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print("Array representation of the binary tree:")
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print(arr)
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print("Linked representation of the binary tree:")
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PrintUtil.printTree(root: root)
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// Binary tree class using an array representation
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let abt = ArrayBinaryTree(arr: arr)
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// Access a node
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let i = 1
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let l = abt.left(i: i)
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let r = abt.right(i: i)
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let p = abt.parent(i: i)
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print("\nCurrent node: index = \(i), value = \(abt.val(i: i) as Any)")
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print("Left child: index = \(l), value = \(abt.val(i: l) as Any)")
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print("Right child: index = \(r), value = \(abt.val(i: r) as Any)")
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print("Parent: index = \(p), value = \(abt.val(i: p) as Any)")
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// Traverse the tree
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var res = abt.levelOrder()
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print("\nLevel-order traversal: \(res)")
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res = abt.preOrder()
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print("Preorder traversal: \(res)")
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res = abt.inOrder()
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print("Inorder traversal: \(res)")
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res = abt.postOrder()
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print("Postorder traversal: \(res)")
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}
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}
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