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* Retranslate the complete English edition from Simplified Chinese * Polish three English explanations after reader-focused review
185 lines
5.0 KiB
Zig
185 lines
5.0 KiB
Zig
// File: time_complexity.zig
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// Created Time: 2022-12-28
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// Author: codingonion (coderonion@gmail.com), CreatorMetaSky (creator_meta_sky@163.com)
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const std = @import("std");
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// Constant complexity
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fn constant(n: i32) i32 {
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_ = n;
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var count: i32 = 0;
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const size: i32 = 100_000;
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var i: i32 = 0;
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while (i < size) : (i += 1) {
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count += 1;
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}
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return count;
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}
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// Linear complexity
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fn linear(n: i32) i32 {
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var count: i32 = 0;
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var i: i32 = 0;
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while (i < n) : (i += 1) {
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count += 1;
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}
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return count;
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}
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// Linear complexity (array traversal)
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fn arrayTraversal(nums: []i32) i32 {
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var count: i32 = 0;
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// The number of iterations is proportional to the array length
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for (nums) |_| {
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count += 1;
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}
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return count;
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}
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// Quadratic complexity
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fn quadratic(n: i32) i32 {
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var count: i32 = 0;
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var i: i32 = 0;
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// The number of iterations is proportional to the square of the input size n
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while (i < n) : (i += 1) {
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var j: i32 = 0;
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while (j < n) : (j += 1) {
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count += 1;
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}
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}
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return count;
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}
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// Quadratic complexity (bubble sort)
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fn bubbleSort(nums: []i32) i32 {
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var count: i32 = 0; // Counter
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// Outer loop: the unsorted range is [0, i]
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var i: i32 = @as(i32, @intCast(nums.len)) - 1;
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while (i > 0) : (i -= 1) {
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var j: usize = 0;
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// Inner loop: move the largest element in the unsorted range [0, i] to its right end through swaps
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while (j < i) : (j += 1) {
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if (nums[j] > nums[j + 1]) {
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// Swap nums[j] and nums[j + 1]
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const tmp = nums[j];
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nums[j] = nums[j + 1];
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nums[j + 1] = tmp;
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count += 3; // Swapping two elements takes 3 elementary operations
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}
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}
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}
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return count;
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}
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// Exponential complexity (iterative implementation)
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fn exponential(n: i32) i32 {
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var count: i32 = 0;
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var bas: i32 = 1;
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var i: i32 = 0;
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// Each cell divides into two per round, giving the sequence 1, 2, 4, 8, ..., 2^(n-1)
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while (i < n) : (i += 1) {
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var j: i32 = 0;
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while (j < bas) : (j += 1) {
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count += 1;
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}
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bas *= 2;
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}
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// count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
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return count;
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}
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// Exponential complexity (recursive implementation)
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fn expRecur(n: i32) i32 {
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if (n == 1) return 1;
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return expRecur(n - 1) + expRecur(n - 1) + 1;
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}
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// Logarithmic complexity (iterative implementation)
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fn logarithmic(n: i32) i32 {
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var count: i32 = 0;
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var n_var: i32 = n;
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while (n_var > 1) : (n_var = @divTrunc(n_var, 2)) {
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count += 1;
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}
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return count;
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}
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// Logarithmic complexity (recursive implementation)
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fn logRecur(n: i32) i32 {
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if (n <= 1) return 0;
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return logRecur(@divTrunc(n, 2)) + 1;
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}
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// Linearithmic complexity
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fn linearLogRecur(n: i32) i32 {
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if (n <= 1) return 1;
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var count: i32 = linearLogRecur(@divTrunc(n, 2)) + linearLogRecur(@divTrunc(n, 2));
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var i: i32 = 0;
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while (i < n) : (i += 1) {
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count += 1;
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}
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return count;
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}
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// Factorial complexity (recursive implementation)
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fn factorialRecur(n: i32) i32 {
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if (n == 0) return 1;
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var count: i32 = 0;
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var i: i32 = 0;
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// Split one problem into n subproblems
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while (i < n) : (i += 1) {
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count += factorialRecur(n - 1);
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}
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return count;
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}
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// Driver code
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pub fn run() void {
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// Try different values of n to see how the operation count grows for each complexity
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const n: i32 = 8;
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std.debug.print("Input size n = {}\n", .{n});
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var count = constant(n);
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std.debug.print("Constant-time operation count = {}\n", .{count});
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count = linear(n);
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std.debug.print("Linear-time operation count = {}\n", .{count});
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var nums = [_]i32{0} ** n;
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count = arrayTraversal(&nums);
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std.debug.print("Linear-time operation count (array traversal) = {}\n", .{count});
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count = quadratic(n);
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std.debug.print("Quadratic-time operation count = {}\n", .{count});
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for (&nums, 0..) |*num, i| {
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num.* = n - @as(i32, @intCast(i)); // [n,n-1,...,2,1]
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}
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count = bubbleSort(&nums);
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std.debug.print("Quadratic-time operation count (bubble sort) = {}\n", .{count});
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count = exponential(n);
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std.debug.print("Exponential-time operation count (iterative) = {}\n", .{count});
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count = expRecur(n);
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std.debug.print("Exponential-time operation count (recursive) = {}\n", .{count});
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count = logarithmic(n);
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std.debug.print("Logarithmic-time operation count (iterative) = {}\n", .{count});
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count = logRecur(n);
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std.debug.print("Logarithmic-time operation count (recursive) = {}\n", .{count});
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count = linearLogRecur(n);
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std.debug.print("Linearithmic-time operation count (recursive) = {}\n", .{count});
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count = factorialRecur(n);
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std.debug.print("Factorial-time operation count (recursive) = {}\n", .{count});
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std.debug.print("\n", .{});
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}
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pub fn main() !void {
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run();
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}
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test "time_complexity" {
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run();
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}
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