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programmercarl
2023-03-10 14:02:32 +08:00
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problems/0188.买卖股票的最佳时机IV.md
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@@ -129,7 +129,7 @@ for (int j = 1; j < 2 * k; j += 2) {
以输入[1,2,3,4,5]，k=2为例。
![188.买卖股票的最佳时机IV](https://img-blog.csdnimg.cn/20201229100358221.png)
![188.买卖股票的最佳时机IV](https://code-thinking-1253855093.file.myqcloud.com/pics/20201229100358221.png)
最后一次卖出，一定是利润最大的，dp[prices.size() - 1][2 * k]即红色部分就是最后求解。