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<p align="center"><strong><a href="https://mp.weixin.qq.com/s/tqCxrMEU-ajQumL1i8im9A">参与本项目</a>,贡献其他语言版本的代码,拥抱开源,让更多学习算法的小伙伴们收益!</strong></p>
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## 746. 使用最小花费爬楼梯
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# 746. 使用最小花费爬楼梯
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[力扣题目链接](https://leetcode-cn.com/problems/min-cost-climbing-stairs/)
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这么写看上去比较顺,但是就是感觉和题目描述的不太符。哈哈,也没有必要这么细扣题意了,大家只要知道,题目的意思反正就是要不是第一步不花费,要不是最后一步不花费,都可以。
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# 总结
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## 总结
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大家可以发现这道题目相对于 昨天的[动态规划:爬楼梯](https://programmercarl.com/0070.爬楼梯.html)有难了一点,但整体思路是一样。
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## 其他语言版本
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Java:
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### Java
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```Java
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class Solution {
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public int minCostClimbingStairs(int[] cost) {
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}
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```
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Python:
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### Python
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```python
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class Solution:
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def minCostClimbingStairs(self, cost: List[int]) -> int:
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return min(dp[len(cost) - 1], dp[len(cost) - 2])
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```
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Go:
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### Go
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```Go
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func minCostClimbingStairs(cost []int) int {
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dp := make([]int, len(cost))
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}
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```
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Javascript:
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### Javascript
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```Javascript
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var minCostClimbingStairs = function(cost) {
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const dp = [ cost[0], cost[1] ]
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