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programmercarl
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problems/0209.长度最小的子数组.md
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解题的关键在于 窗口的起始位置如何移动，如图所示：
![leetcode_209](https://code-thinking-1253855093.file.myqcloud.com/pics/20210312160441942.png)
![leetcode_209](https://file.kamacoder.com/pics/20210312160441942.png)
可以发现**滑动窗口的精妙之处在于根据当前子序列和大小的情况，不断调节子序列的起始位置。从而将O(n^2)暴力解法降为O(n)。**