更新代码块

problems/0583.两个字符串的删除操作.md

@@ -56,7 +56,7 @@ dp[i][0]：word2为空字符串，以i-1为结尾的字符串word2要删除多
 
 dp[0][j]的话同理，所以代码如下：
 
-```C++
+```CPP
 vector<vector<int>> dp(word1.size() + 1, vector<int>(word2.size() + 1));
 for (int i = 0; i <= word1.size(); i++) dp[i][0] = i;
 for (int j = 0; j <= word2.size(); j++) dp[0][j] = j;
@@ -78,7 +78,7 @@ for (int j = 0; j <= word2.size(); j++) dp[0][j] = j;
 
 以上分析完毕，代码如下：
 
-```C++
+```CPP
 class Solution {
 public:
     int minDistance(string word1, string word2) {