From d9887223965e84771503808e5685c1307998fabe Mon Sep 17 00:00:00 2001
From: jianghongcheng <35664721+jianghongcheng@users.noreply.github.com>
Date: Wed, 31 May 2023 23:44:40 -0500
Subject: [PATCH] =?UTF-8?q?Update=200053.=E6=9C=80=E5=A4=A7=E5=AD=90?=
 =?UTF-8?q?=E5=BA=8F=E5=92=8C.md?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 problems/0053.最大子序和.md | 26 ++++++++++++++++++++------
 1 file changed, 20 insertions(+), 6 deletions(-)

diff --git a/problems/0053.最大子序和.md b/problems/0053.最大子序和.md
index 48f8be29..bc5e1d55 100644
--- a/problems/0053.最大子序和.md
+++ b/problems/0053.最大子序和.md
@@ -198,21 +198,35 @@ class Solution {
 ```
 
 ### Python
-
+暴力法
 ```python
 class Solution:
-    def maxSubArray(self, nums: List[int]) -> int:
-        result = -float('inf')
+    def maxSubArray(self, nums):
+        result = float('-inf')  # 初始化结果为负无穷大
+        count = 0
+        for i in range(len(nums)):  # 设置起始位置
+            count = 0
+            for j in range(i, len(nums)):  # 从起始位置i开始遍历寻找最大值
+                count += nums[j]
+                result = max(count, result)  # 更新最大值
+        return result
+
+```
+```python
+class Solution:
+    def maxSubArray(self, nums):
+        result = float('-inf')  # 初始化结果为负无穷大
         count = 0
         for i in range(len(nums)):
             count += nums[i]
-            if count > result:
+            if count > result:  # 取区间累计的最大值（相当于不断确定最大子序终止位置）
                 result = count
-            if count <= 0:
+            if count <= 0:  # 相当于重置最大子序起始位置，因为遇到负数一定是拉低总和
                 count = 0
         return result
-```
 
+
+```
 ### Go
 
 ```go