diff --git a/math/sqrt_double.cpp b/math/sqrt_double.cpp
index 5a0fd1c88..1521b500a 100644
--- a/math/sqrt_double.cpp
+++ b/math/sqrt_double.cpp
@@ -1,27 +1,35 @@
-#include <iostream>
+/**
+ * @file
+ * @brief Calculate the square root of any positive number in \f$O(\log N)\f$
+ * time, with precision fixed using [bisection
+ * method](https://en.wikipedia.org/wiki/Bisection_method) of root-finding.
+ *
+ * @see Can be implemented using faster and better algorithms like
+ * newton_raphson_method.cpp and false_position.cpp
+ */
 #include <cassert>
+#include <iostream>
 
-/* Calculate the square root of any 
-number in O(logn) time, 
-with precision fixed */
-
-double Sqrt(double x) {
-    if ( x > 0 && x < 1 ) {
-        return 1/Sqrt(1/x);
+/** Bisection method implemented for the function \f$x^2-a=0\f$
+ * whose roots are \f$\pm\sqrt{a}\f$ and only the positive root is returned.
+ */
+double Sqrt(double a) {
+    if (a > 0 && a < 1) {
+        return 1 / Sqrt(1 / a);
     }
-    double l = 0, r = x;
-    /* Epsilon is the precision. 
-    A great precision is 
+    double l = 0, r = a;
+    /* Epsilon is the precision.
+    A great precision is
     between 1e-7 and 1e-12.
     double epsilon = 1e-12;
     */
     double epsilon = 1e-12;
-    while ( l <= r ) {
+    while (l <= r) {
         double mid = (l + r) / 2;
-        if ( mid * mid > x ) {
+        if (mid * mid > a) {
             r = mid;
         } else {
-            if ( x - mid * mid < epsilon ) {
+            if (a - mid * mid < epsilon) {
                 return mid;
             }
             l = mid;
@@ -29,11 +37,13 @@ double Sqrt(double x) {
     }
     return -1;
 }
+
+/** main function */
 int main() {
-  double n{};
-  std::cin >> n;
-  assert(n >= 0);
-  // Change this line for a better precision
-  std::cout.precision(12);
-  std::cout << std::fixed << Sqrt(n);
+    double n{};
+    std::cin >> n;
+    assert(n >= 0);
+    // Change this line for a better precision
+    std::cout.precision(12);
+    std::cout << std::fixed << Sqrt(n);
 }