From 7a13a35dfd6d4563d5dab7db3547b5e8f131fc61 Mon Sep 17 00:00:00 2001
From: Anushka Verma <v.anushka786@gmail.com>
Date: Mon, 24 Aug 2020 01:47:16 +0530
Subject: [PATCH] feat: add word break solution (backtracking)

---
 backtracking/word_break.cpp | 50 +++++++++++++++++++++++++++++++++++++
 1 file changed, 50 insertions(+)
 create mode 100644 backtracking/word_break.cpp

diff --git a/backtracking/word_break.cpp b/backtracking/word_break.cpp
new file mode 100644
index 000000000..b41a6aa77
--- /dev/null
+++ b/backtracking/word_break.cpp
@@ -0,0 +1,50 @@
+/**
+ * @file Word Break 
+ * 
+ * @details
+ * Given a valid sentence without any spaces between the words and 
+ * a dictionary of valid English words, find all possible ways to 
+ * break the sentence in individual dictionary words.
+ *
+ * @author [Anushka Verma](https://github.com/verma-anushka)
+ */
+
+#include <bits/stdc++.h>
+using namespace std;
+
+/**
+ * Utility function
+ */
+void wordbreak(string s, vector<string>& dict, int i, string ans) {
+    
+    string word=s.substr(0, i+1);
+    int ws=s.size();
+
+    // search for word in the dictionary
+    if(find(dict.begin(), dict.end(), word) != dict.end()) {
+
+        if(i<ws-1)
+            // recursive call
+            wordbreak(s.substr(i+1, ws-i), dict, 0, ans+word+" ");
+        else
+            // print output
+            cout << (ans+word) << endl;
+    }
+    if(i<ws-1)
+        wordbreak(s, dict, i+1, ans);
+
+}
+
+/**
+ * Main function
+ */
+int main() {
+
+    vector<string> dict = { "mobile","samsung","sam","sung", 
+                            "man","mango","icecream","and", 
+                            "go","i","like","ice","cream" };
+    string s = "ilikesamsung";
+    wordbreak(s, dict, 0, "");
+    return 0;
+}
+