feat: Modify search/text_search.cpp (#1662)

* Modified search/text_search.cpp

* Added tests

* Added a few test cases

* Added a few more test cases and documentation

* Minor fix

* Minor fixes

* Minor fixes

* Minor output fixes

* Minor output fixes

* Minor readability fixes

* clang-format and clang-tidy fixes for a01765a6

* Restored original settings

* clang-format and clang-tidy fixes for 6a8f3a4e

Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: David Leal <halfpacho@gmail.com>

dynamic_programming/armstrong_number.cpp

@@ -1,6 +1,6 @@
 // Program to check whether a number is an armstrong number or not
-#include <iostream>
 #include <cmath>
+#include <iostream>
 using std::cin;
 using std::cout;
 
@@ -8,34 +8,32 @@ int main() {
     int n = 0, temp = 0, rem = 0, count = 0, sum = 0;
     cout << "Enter a number: ";
     cin >> n;
-    
+
     temp = n;
-    
+
     /* First Count the number of digits
        in the given number */
-    while(temp != 0) {
+    while (temp != 0) {
         temp /= 10;
         count++;
     }
 
-    /* Calaculation for checking of armstrongs number i.e. 
+    /* Calaculation for checking of armstrongs number i.e.
        in a n digit number sum of the digits raised to a power of n
        is equal to the original number */
-    
+
     temp = n;
-    while(temp!=0) {
-        rem = temp%10;
-        sum += (int) pow(rem,count);
-        temp/=10;
+    while (temp != 0) {
+        rem = temp % 10;
+        sum += static_cast<int>(pow(rem, count));
+        temp /= 10;
     }
-    
 
     if (sum == n) {
         cout << n << " is an armstrong number";
-    }
-    else {
+    } else {
         cout << n << " is not an armstrong number";
     }
-    
+
     return 0;
 }