Merge branch 'scheduling' of https://github.com/Pratyush219/C-Plus-Plus into scheduling

cpu_scheduling_algorithms/fcfs_scheduling.cpp

@@ -8,15 +8,15 @@
  * @author [Pratyush Vatsa](https://github.com/Pratyush219)
  */
 
-#include <iostream>       /// for IO operations
-#include <queue>          /// for std::priority_queue
-#include <unordered_set>  /// for std::unordered_set
-#include <vector>         /// for std::vector
 #include <algorithm>      /// for sorting
 #include <cassert>        /// for assert
 #include <cstdlib>        /// random number generation
 #include <ctime>          /// for time
 #include <iomanip>        /// for formatting the output
+#include <iostream>       /// for IO operations
+#include <queue>          /// for std::priority_queue
+#include <unordered_set>  /// for std::unordered_set
+#include <vector>         /// for std::vector
 
 using std::cin;
 using std::cout;
@@ -271,7 +271,8 @@ void test() {
             readyQueue.addProcess(get<0>(input[i]), get<1>(input[i]),
                                   get<2>(input[i]));
         }
-        vector<tuple<uint32_t, uint32_t, uint32_t, double, double, double>> res = get_final_status<uint32_t, uint32_t, uint32_t>(input);
+        vector<tuple<uint32_t, uint32_t, uint32_t, double, double, double>>
+            res = get_final_status<uint32_t, uint32_t, uint32_t>(input);
         assert(res == readyQueue.scheduleForFcfs());
         // readyQueue.printResult();
     }

dynamic_programming/armstrong_number.cpp

@@ -1,21 +1,39 @@
 // Program to check whether a number is an armstrong number or not
+#include <cmath>
 #include <iostream>
-
 using std::cin;
 using std::cout;
 
 int main() {
-    int n, k, d, s = 0;
-    cout << "Enter a number:";
+    int n = 0, temp = 0, rem = 0, count = 0, sum = 0;
+    cout << "Enter a number: ";
     cin >> n;
-    k = n;
-    while (k != 0) {
-        d = k % 10;
-        s += d * d * d;
-        k /= 10;
+
+    temp = n;
+
+    /* First Count the number of digits
+       in the given number */
+    while (temp != 0) {
+        temp /= 10;
+        count++;
     }
-    if (s == n)
-        cout << n << "is an armstrong number";
-    else
-        cout << n << "is not an armstrong number";
+
+    /* Calaculation for checking of armstrongs number i.e.
+       in a n digit number sum of the digits raised to a power of n
+       is equal to the original number */
+
+    temp = n;
+    while (temp != 0) {
+        rem = temp % 10;
+        sum += static_cast<int>(pow(rem, count));
+        temp /= 10;
+    }
+
+    if (sum == n) {
+        cout << n << " is an armstrong number";
+    } else {
+        cout << n << " is not an armstrong number";
+    }
+
+    return 0;
 }