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realstealthninja
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<div class="headertitle"><div class="title">binary_exponent.cpp File Reference</div></div>
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Include dependency graph for binary_exponent.cpp:</div>
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<p><a href="../../de/dcf/binary__exponent_8cpp_source.html">Go to the source code of this file.</a></p>
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Functions</h2></td></tr>
<tr class="memitem:aeb48dce0725e63d19147944f41843c73" id="r_aeb48dce0725e63d19147944f41843c73"><td class="memItemLeft" align="right" valign="top">int&#160;</td><td class="memItemRight" valign="bottom"><a class="el" href="#aeb48dce0725e63d19147944f41843c73">binExpo</a> (int a, int b)</td></tr>
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<tr class="memdesc:ae66f6b31b5ad750f1fe042a706a4e3d4"><td class="mdescLeft">&#160;</td><td class="mdescRight">Main function. <br /></td></tr>
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<a name="details" id="details"></a><h2 class="groupheader">Detailed Description</h2>
<a name="details" id="details"></a><h2 id="header-details" class="groupheader">Detailed Description</h2>
<div class="textblock"><p>C++ Program to find Binary Exponent Iteratively and Recursively. </p>
<p>Calculate \(a^b\) in \(O(\log(b))\) by converting \(b\) to a binary number. Binary exponentiation is also known as exponentiation by squaring. </p><dl class="section note"><dt>Note</dt><dd>This is a far better approach compared to naive method which provide \(O(b)\) operations.</dd></dl>
<p>Example: 10 in base 2 is 1010. </p><p class="formulaDsp">
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<p> Hence to calculate 2^10 we only need to multiply \(2^8\) and \(2^2\) skipping \(2^1\) and \(2^4\). </p>
<p class="definition">Definition in file <a class="el" href="../../de/dcf/binary__exponent_8cpp_source.html">binary_exponent.cpp</a>.</p>
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<h2 class="memtitle"><span class="permalink"><a href="#aeb48dce0725e63d19147944f41843c73">&#9670;&#160;</a></span>binExpo()</h2>
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