Files
C-Plus-Plus/math/vector_cross_product.cpp
Piotr Idzik b9c118fb5d style: remove interaction with the user (#3009)
* style: remove interaction with the user

Helps with #2753

* clang-format and clang-tidy fixes for ff441e08

* tests: add test with result being a zero vector

Co-authored-by: realstealthninja <68815218+realstealthninja@users.noreply.github.com>

---------

Co-authored-by: github-actions[bot] <github-actions[bot]@users.noreply.github.com>
Co-authored-by: realstealthninja <68815218+realstealthninja@users.noreply.github.com>
2025-10-11 14:49:11 +00:00

133 lines
4.3 KiB
C++
Raw Permalink Blame History

This file contains ambiguous Unicode characters
This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.
/**
* @file
*
* @brief Calculates the [Cross
*Product](https://en.wikipedia.org/wiki/Cross_product) and the magnitude of two
*mathematical 3D vectors.
*
*
* @details Cross Product of two vectors gives a vector.
* Direction Ratios of a vector are the numeric parts of the given vector. They
*are the tree parts of the vector which determine the magnitude (value) of the
*vector. The method of finding a cross product is the same as finding the
*determinant of an order 3 matrix consisting of the first row with unit vectors
*of magnitude 1, the second row with the direction ratios of the first vector
*and the third row with the direction ratios of the second vector. The
*magnitude of a vector is it's value expressed as a number. Let the direction
*ratios of the first vector, P be: a, b, c Let the direction ratios of the
*second vector, Q be: x, y, z Therefore the calculation for the cross product
*can be arranged as:
*
* ```
* P x Q:
* 1 1 1
* a b c
* x y z
* ```
*
* The direction ratios (DR) are calculated as follows:
* 1st DR, J: (b * z) - (c * y)
* 2nd DR, A: -((a * z) - (c * x))
* 3rd DR, N: (a * y) - (b * x)
*
* Therefore, the direction ratios of the cross product are: J, A, N
* The following C++ Program calculates the direction ratios of the cross
*products of two vector. The program uses a function, cross() for doing so. The
*direction ratios for the first and the second vector has to be passed one by
*one seperated by a space character.
*
* Magnitude of a vector is the square root of the sum of the squares of the
*direction ratios.
*
* ### Example:
* An example of a running instance of the executable program:
*
* Pass the first Vector: 1 2 3
* Pass the second Vector: 4 5 6
* The cross product is: -3 6 -3
* Magnitude: 7.34847
*
* @author [Shreyas Sable](https://github.com/Shreyas-OwO)
*/
#include <array>
#include <cassert>
#include <cmath>
/**
* @namespace math
* @brief Math algorithms
*/
namespace math {
/**
* @namespace vector_cross
* @brief Functions for Vector Cross Product algorithms
*/
namespace vector_cross {
/**
* @brief Function to calculate the cross product of the passed arrays
* containing the direction ratios of the two mathematical vectors.
* @param A contains the direction ratios of the first mathematical vector.
* @param B contains the direction ration of the second mathematical vector.
* @returns the direction ratios of the cross product.
*/
std::array<double, 3> cross(const std::array<double, 3> &A,
const std::array<double, 3> &B) {
std::array<double, 3> product;
/// Performs the cross product as shown in @algorithm.
product[0] = (A[1] * B[2]) - (A[2] * B[1]);
product[1] = -((A[0] * B[2]) - (A[2] * B[0]));
product[2] = (A[0] * B[1]) - (A[1] * B[0]);
return product;
}
/**
* @brief Calculates the magnitude of the mathematical vector from it's
* direction ratios.
* @param vec an array containing the direction ratios of a mathematical vector.
* @returns type: double description: the magnitude of the mathematical vector
* from the given direction ratios.
*/
double mag(const std::array<double, 3> &vec) {
double magnitude =
sqrt((vec[0] * vec[0]) + (vec[1] * vec[1]) + (vec[2] * vec[2]));
return magnitude;
}
} // namespace vector_cross
} // namespace math
/**
* @brief test function.
* @details test the cross() and the mag() functions.
*/
static void test() {
/// Tests the cross() function.
std::array<double, 3> t_vec =
math::vector_cross::cross({1, 2, 3}, {4, 5, 6});
assert(t_vec[0] == -3 && t_vec[1] == 6 && t_vec[2] == -3);
/// Tests the mag() function.
double t_mag = math::vector_cross::mag({6, 8, 0});
assert(t_mag == 10);
/// Tests A A = 0
std::array<double, 3> t_vec2 =
math::vector_cross::cross({1, 2, 3}, {1, 2, 3});
assert(t_vec2[0] == 0 && t_vec2[1] == 0 &&
t_vec2[2] == 0); // checking each element
assert(math::vector_cross::mag(t_vec2) ==
0); // checking the magnitude is also zero
}
/**
* @brief Main Function
* @details Asks the user to enter the direction ratios for each of the two
* mathematical vectors using std::cin
* @returns 0 on exit
*/
int main() {
/// Tests the functions with sample input before asking for user input.
test();
return 0;
}