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* updated the code to make it more efficient * Update math/check_prime.cpp Co-authored-by: David Leal <halfpacho@gmail.com> * Update math/check_prime.cpp Co-authored-by: David Leal <halfpacho@gmail.com> * Apply suggestions from code review Co-authored-by: David Leal <halfpacho@gmail.com>
63 lines
1.7 KiB
C++
63 lines
1.7 KiB
C++
/**
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* Copyright 2020 @author omkarlanghe
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*
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* @file
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* A simple program to check if the given number if prime or not.
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*
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* @brief
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* Reduced all possibilities of a number which cannot be prime.
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* Eg: No even number, except 2 can be a prime number, hence we will increment
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* our loop with i+6 jumping and check for i or i+2 to be a factor of the number;
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* if it's a factor then we will return false otherwise true after the loop terminates at the terminating condition which is (i*i<=num)
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*/
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#include <cassert> /// for assert
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#include <iostream> /// for IO operations
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/**
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* Function to check if the given number is prime or not.
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* @param num number to be checked.
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* @return if number is prime, it returns @ true, else it returns @ false.
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*/
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template <typename T>
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bool is_prime(T num) {
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bool result = true;
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if (num <= 1) {
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return false;
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} else if (num == 2 || num==3) {
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return true;
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} else if ((num%2) == 0 || num%3 == 0) {
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return false;
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}
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else {
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for (T i = 5; (i * i) <= (num); i = (i + 6)) {
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if ((num % i) == 0 || (num%(i+2)==0 )) {
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result = false;
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break;
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}
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}
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}
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return (result);
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}
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/**
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* Main function
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*/
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int main() {
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// perform self-test
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assert(is_prime(50) == false);
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assert(is_prime(115249) == true);
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int num = 0;
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std::cout << "Enter the number to check if it is prime or not" << std::endl;
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std::cin >> num;
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bool result = is_prime(num);
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if (result) {
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std::cout << num << " is a prime number" << std::endl;
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} else {
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std::cout << num << " is not a prime number" << std::endl;
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}
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return 0;
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}
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