第三章 栈和队列更新完毕

栈和队列/栈和队列的应用/P96.1.cpp

@@ -0,0 +1,61 @@
+#include <iostream>
+#include <stack>
+#include <string>
+
+using namespace std;
+
+#define _for(i,a,b) for(int i=(a);i<(b);i++)
+
+void Bracket_Pairing() {
+
+//	test:  "a+{[b*(c-d)]*e+f/(g-h)}*I";
+//	test:  "a+{[b*(c-d)]]*e+f/(g-h)}*I)";
+
+	string s;
+	getline(cin, s);
+	stack<char> bracket;
+	_for(i, 0, s.size()) {
+		if (s[i] == '(' || s[i] == '{' || (s[i] == '[')) {
+			bracket.push(s[i]);
+		}
+		if (s[i] == ')' || s[i] == '}' || (s[i] == ']')) {
+
+			char Parentheses = bracket.top();
+			switch (Parentheses)
+			{
+				case '(': {
+					if (s[i] == ')') {
+						bracket.pop();
+						break;
+					}
+				}
+				case '[': {
+					if (s[i] == ']') {
+						bracket.pop();
+						break;
+					}
+				}
+				case '{': {
+					if (s[i] == '}') {
+						bracket.pop();
+						break;
+					}
+				}
+				default: {
+					cout << "匹配失败!" << endl;
+					return;
+				}
+			}
+		}
+	}
+	if (bracket.empty()) {
+		cout << "匹配成功！" << endl;
+	}
+	return;
+}
+int main()
+{
+	Bracket_Pairing();
+	return 0;
+}
+

栈和队列/栈和队列的应用/P96.2.cpp

@@ -0,0 +1,41 @@
+#include <iostream>
+#include <stack>
+#include <string>
+
+using namespace std;
+
+#define _for(i,a,b) for(int i=(a);i<(b);i++)
+
+//P96.2
+//按下图所示铁道进行车厢调度(注意, 两侧铁道均为单向行驶道, 火车调度站有一个用
+//于调度的“栈道”), 火车调度站的入口处有n节硬座和软座车厢(分别用H和S表示)
+//等待调度, 试编写算法, 输出对这n节车厢迸行调度的操作(即入栈或出栈操作)序列,
+//以使所有的软座车厢都被调整到硬座车厢之前。
+
+string Arrange(string sats) {
+
+    stack<char> arr;
+    string s;
+    int j = 0;
+    _for(i, 0, sats.size()) {
+        if (sats[i] == 'S') {
+            s += sats[i];
+        }
+        else {
+            arr.push(sats[i]);
+        }
+    }
+    while (!arr.empty()) {
+        s += arr.top();
+        arr.pop();
+    }
+    return s;
+}
+
+int main()
+{
+    string sats= "HSSSHHHSSHHHHHSSHHSSHSHSHSHS";
+    cout << Arrange(sats) << endl;
+    return 0;
+}
+

栈和队列/栈和队列的应用/P96.3.cpp

@@ -0,0 +1,44 @@
+#include <iostream>
+#include <string>
+
+using namespace std;
+
+#define _for(i,a,b) for(int i=(a);i<(b);i++)
+#define MaxSize 30
+//P96.3
+//利用一个栈实现以下递归函数的非递归计算:
+//            1                                          n = 0
+//    Pn(x) = 2x                                         n = 1
+//            2x * Pn-1(x) - 2(n - 1) * Pn-2(x)          n > 1
+
+//直接用数组实现不是更方便 -> ->
+
+double Calculate(int n,double x) {
+    struct stack {
+        int number;
+        double value;
+    }Sqstack[MaxSize];
+    int top = -1, i;
+    double f1 = 1, f2 = 2 * x;
+    for (i = n; i >= 2; i--) {
+        top++;
+        Sqstack[top].number = i;
+    }
+    while (top >= 0) {
+        Sqstack[top].value = 2 * x * f2 - 2 * (Sqstack[top].number - 1) * f1;
+        f1 = f2;
+        f2 = Sqstack[top].value;
+        top--;
+    }
+    if (n == 0) {
+        return f1;
+    }
+    return f2;
+}
+
+int main()
+{
+    cout << Calculate(6,3.14) << endl;
+    return 0;
+}
+

栈和队列/栈和队列的应用/P96.4.cpp

@@ -0,0 +1,113 @@
+#include <iostream>
+#include <stack>
+#include <string>
+#include <queue>
+using namespace std;
+
+#define _for(i,a,b) for(int i=(a);i<(b);i++)
+#define MaxSize 10
+#define WaitCars 23
+#define BusNum 7
+#define TrackNum 2
+struct Cars {
+    int id;
+    string type;  //货车：Track 客车：Bus
+};
+
+
+//P96.4
+//某汽车轮渡口, 过江渡船毎次能载10辆车过江。过江车辆分为客车类和货车类, 上渡船
+//有如下规定 : 同类车先到先上船; 客车先于货车上船, 且每上4辆客车, 才允许放上1
+//辆货车; 若等待客车不足4辆, 则以货车代替; 若无货车等待, 允许客车都上船。试设
+//计一个算法模拟渡口管理。
+
+#pragma region P96.4
+
+queue<Cars> Bus, Trucks, CarList;
+
+
+void Load_PassCar() {
+    Cars c;
+    c.id = -999;
+    if (!Bus.empty()) {
+        c = Bus.front();
+        Bus.pop();
+        CarList.push(c);
+    }
+    else {
+        if (!Trucks.empty()) {
+            c = Trucks.front();
+            Trucks.pop();
+            CarList.push(c);
+        }
+    }
+    if (c.id != -999)
+        cout << "第" << c.id << "号" << c.type << "上船" << endl;
+}
+
+void Load_Track() {
+    Cars c;
+    c.id = -999;
+    if (!Trucks.empty()) {
+        c = Trucks.front();
+        Trucks.pop();
+        CarList.push(c);
+    }
+    else {
+        if (!Trucks.empty()) {
+            c = Bus.front();
+            Bus.pop();
+            CarList.push(c);
+        }
+    }
+    if (c.id != -999)
+        cout << "第" << c.id << "号" << c.type << "上船" << endl;
+}
+
+
+
+void Ferry_Manage() {
+    int Bus_Count = 0;
+    int MaxNum = 0;
+    while (MaxNum < 10)
+    {
+        if (Bus_Count != 4) {
+            Bus_Count++;
+            MaxNum++;
+            Load_PassCar();
+        }
+        if (Bus_Count == 4) {
+            Bus_Count = 0;
+            MaxNum++;
+            Load_Track();
+        }
+    }
+}
+
+
+
+#pragma endregion
+
+//test
+void Init() {
+    //Bus
+    _for(i, 0, BusNum) {
+        Cars t;
+        t.id = i, t.type = "Bus";
+        Bus.push(t);
+    }
+    //Track
+   _for(i, 0, TrackNum) {
+       Cars t;
+       t.id = i, t.type = "Track";
+       Trucks.push(t);
+   }
+}
+
+int main()
+{
+    Init();
+    Ferry_Manage();
+    return 0;
+}
+