Create 2024_unique_topology_order.cpp

新增2024年算法题

2024_unique_topology_order.cpp

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+#include <iostream>
+#include <queue>
+#include <vector>
+
+#define MAXV 100 // 假设最大顶点数为100
+
+typedef struct {
+    int numberVertices, numberEdges; // 图的顶点数和边数
+    char VerticesList[MAXV];         // 顶点表
+    int edge[MAXV][MAXV];            // 邻接矩阵
+} MGraph;
+
+// 判断图是否有唯一的拓扑序列
+int intquely(MGraph G) {
+    std::vector<int> inDegree(G.numberVertices, 0);
+    std::queue<int> q;
+
+    // 计算每个顶点的入度
+    for (int i = 0; i < G.numberVertices; ++i) {
+        for (int j = 0; j < G.numberVertices; ++j) {
+            if (G.edge[i][j] != 0) {
+                inDegree[j]++;
+            }
+        }
+    }
+
+    // 找到所有入度为0的顶点并加入队列
+    for (int i = 0; i < G.numberVertices; ++i) {
+        if (inDegree[i] == 0) {
+            q.push(i);
+        }
+    }
+
+    std::vector<int> topoOrder;
+
+    while (!q.empty()) {
+        if (q.size() > 1) { // 入度为0的顶点不唯一
+            return 0;
+        }
+        
+        int v = q.front();
+        q.pop();
+        topoOrder.push_back(v);
+
+        for (int i = 0; i < G.numberVertices; ++i) {
+            if (G.edge[v][i] != 0) {
+                inDegree[i]--;
+                if (inDegree[i] == 0) {
+                    q.push(i);
+                }
+            }
+        }
+    }
+
+    // 若拓扑排序包含了所有顶点，则说明图有唯一的拓扑序列
+    return (topoOrder.size() == G.numberVertices) ? 1 : 0;
+}