Book4_Power-of-Matrix/Book4_Ch04_Python_Codes/Bk4_Ch04_04.ipynb

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    "Chapter 04\n",
    "\n",
    "# 矩阵标量乘法\n",
    "Book_4《矩阵力量》 | 鸢尾花书：从加减乘除到机器学习 (第二版)"
   ]
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    "该代码定义了一个标量 $k = 2$ 和一个 $2 \\times 2$ 矩阵 $X$：\n",
    "\n",
    "$$\n",
    "X = \\begin{bmatrix} 1 & 2 \\\\ 3 & 4 \\end{bmatrix}\n",
    "$$\n",
    "\n",
    "代码随后计算了标量 $k$ 与矩阵 $X$ 的乘积，得到的结果矩阵 $k \\times X$ 为：\n",
    "\n",
    "$$\n",
    "k \\times X = 2 \\times \\begin{bmatrix} 1 & 2 \\\\ 3 & 4 \\end{bmatrix} = \\begin{bmatrix} 2 & 4 \\\\ 6 & 8 \\end{bmatrix}\n",
    "$$\n",
    "\n",
    "代码展示了使用 `np.dot` 函数和直接标量乘法来实现标量与矩阵乘积的两种方法。"
   ]
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  {
   "cell_type": "markdown",
   "id": "9b646351-bc61-4c43-96ed-a265eb25eaac",
   "metadata": {},
   "source": [
    "## 导入所需库"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "id": "9a74e2ab-fc70-43a4-85f6-3ddeeacfc5ab",
   "metadata": {},
   "outputs": [],
   "source": [
    "import numpy as np  # 导入NumPy库，用于数值计算"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "6bf76475-2000-4adb-82bf-33664ee781da",
   "metadata": {},
   "source": [
    "## 定义标量和矩阵"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "id": "e74e9afd-6c86-4ccd-bd9e-4382bfe0c31f",
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   "outputs": [],
   "source": [
    "k = 2  # 定义标量k"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "id": "db0ca529-60e7-4093-8942-8976a5bc8b29",
   "metadata": {},
   "outputs": [],
   "source": [
    "X = [[1, 2], \n",
    "     [3, 4]]  # 定义矩阵X"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "8a306144-ae4b-4b29-9b1a-9a4282ef2f21",
   "metadata": {},
   "source": [
    "## 标量与矩阵的乘法"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "id": "33380485-bdda-4392-8ace-7e11690f111b",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "array([[2, 4],\n",
       "       [6, 8]])"
      ]
     },
     "execution_count": 4,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "k_times_X = np.dot(k, X)  # 使用np.dot计算k和X的标量乘法\n",
    "k_times_X"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "id": "be39b596-ea34-4108-9447-e3a46d21f91c",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "matrix([[2, 4],\n",
       "        [6, 8]])"
      ]
     },
     "execution_count": 5,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "k_times_X_2 = k * np.matrix(X)  # 使用*操作符计算k和X的标量乘法\n",
    "k_times_X_2"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "85a80909-2aac-49ed-bb7a-f8cc6b80ee7d",
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   "outputs": [],
   "source": []
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   "cell_type": "code",
   "execution_count": null,
   "id": "ecd322f4-f919-4be2-adc3-69d28ef25e69",
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