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Added LIS O(nlogn)
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//Program to calculate length of longest increasing subsequence in an array
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// in O(n log n)
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// tested on : https://cses.fi/problemset/task/1145/
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#include <bits/stdc++.h>
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using namespace std;
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int LIS(int arr[], int n)
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{
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set<int> active; // The current built LIS.
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active.insert(arr[0]);
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// Loop through every element.
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for(int i=1; i<n; ++i){
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auto get = active.lower_bound(arr[i]);
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if( get == active.end() ){ active.insert(arr[i]); } // current element is the greatest so LIS increases by 1.
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else{
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int val = *get; // we find the position where arr[i] will be in the LIS. If it is in the LIS already we do nothing
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if( val > arr[i] ){
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// else we remove the bigger element and add a smaller element (which is arr[i]) and continue;
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active.erase(get);
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active.insert(arr[i]);
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}
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}
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}
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return active.size(); // size of the LIS.
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}
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int main(int argc, char const *argv[])
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{
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int n;
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cout << "Enter size of array: ";
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cin >> n;
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int a[n];
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cout << "Enter array elements: ";
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for (int i = 0; i < n; ++i)
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{
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cin >> a[i];
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}
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cout << LIS(a, n) << endl;
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return 0;
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}
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