🏐 编辑源增加状态排序, 修复换源功能里源的标识问题. 优化搜索结果样式变形

src/assets/scss/style.scss

@@ -152,7 +152,7 @@
           &.name{
             flex: 1;
             min-width: 100px;
-            white-space: nowrap;
+            overflow: hidden;
             margin-left: 10px;
           }
           &.type{

src/components/EditSites.vue

@@ -54,7 +54,11 @@
               <el-button type="text">{{scope.row.group}}</el-button>
             </template>
           </el-table-column>
-          <el-table-column label="状态" width="120">
+          <el-table-column
+            label="状态"
+            sortable
+            :sort-by="['status']"
+            width="120">
             <template slot-scope="scope">
               <span v-show="scope.row.status === ''">
                 <i class="el-icon-loading"></i>

src/components/Film.vue

@@ -88,11 +88,7 @@
                 <li v-for="(i, j) in searchContents" :key="j" @click="detailEvent(i.site, i)">
                   <span class="name">{{i.name}}</span>
                   <span class="info">{{i.site.name}}</span>
-                  <span class="info">{{i.director}}</span>
                   <span class="info">{{i.type}}</span>
-                  <span class="info">{{i.area}}</span>
-                  <span class="info">{{i.lang}}</span>
-                  <span class="info">{{i.year}}</span>
                   <span class="info">{{i.note}}</span>
                   <span class="operate">
                     <span class="btn" @click.stop="playEvent(i.site, i)">播放</span>

src/components/Play.vue

@@ -757,7 +757,7 @@ export default {
               searchRes.forEach(async item => {
                 const detailRes = item
                 detailRes.key = i.key
-                detailRes.site = item.name
+                detailRes.site = i.site
                 this.right.other.push(detailRes)
               })
             }
@@ -768,7 +768,7 @@ export default {
               this.right.other.push(detailRes)
             }
           } catch (err) {
-            console.log(err)
+            console.error(err)
           }
         }
       }