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Didnelpsun
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/.vscode/
*.aux
*.log
*.pdf
*.synctex.gz
*.toc
*.out

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$\lim\limits_{x\to 1}\dfrac{f(x)}{x-1}=2$$f(x)$连续,可以推出$f(1)=0$$f'(1)=2$
\section{函数求导法则}
\subsection{四则运算}